Metodos Descriptivos

En una gasolinera quieren saber cuántos empleados más deben contratar y para qué turnos, para ello, registraron durante dos días la cantidad de litros de diesel que se vende por hora enla gasolinera, el registro que obtuvieron fue el siguiente:
816 810 856 888 833 839 853 837 881 873 889 836 815 860 830 888 830844 830 831 840 844 840 858 810 888 883 835 884 849 856 888833 869 835 835 884 849 844 840 858 853 837 881 873 889 836 815
Re= máx – min = 889-810= 79

=816+810+856+888+833+839+853+837+881+873+889+836+815+860+830+888+830+844+830+831+840+844+840+858+810+888+883+835+884+849+856+888+833+869+835+835+884+849
+844+840+858+853+837+881+873+889+836+815/48 = 850.9
VARIANZA

N
=(816-850.9)²+(810-850.9)²+(856-850.9)²+(888-850.9)²+(833-850.9)²+(839-850.9)²+(853-850.9)²+(837-850.9)²
+(881-850.9)²+(873-850.9)²+(889-850.9)²+(836-850.9)²+(815-850.9)²+(860.850.9)²+(830-850.9)²+(888-850.9)²+(830-850.9)²+(844-850.9)²+ (830-850.9)²+(831-850.9)²+(840-850.9)²+(844-850.9)²+(840-850.9)²+(858-850.9)²+(810-850.9)²+(888-850.9)²+(883-850.9)+(835-850.9)²+(835-850.9)²+(884-850.9)²+(849-850.9)²+(856-850.9)²
+ (888-850.9)²+(833-850.9)²+(869-850.9)²+(835-850.9)²+(884-850.9)²+(849-859.9)²+(844-850.9)²+(840-850.9)²+(858-850.9)²+(853-850.9)²+(837-850.9)²+(881-850.9)²+(873-850.9)²+(889-850.9)²+(836-850.9)²+(815-850.9)²
/48=
σ²= (1218.01)+(1672.81)+(26.01)+(1376.41)+(320.41)+(141.61)+(4.41)+(193.21)+(902.01)+(488.41)+(1451.61)+(222.01)+(1288.81)+(82.81)+(436.81)+(1376.41)+(436.81)+(47.61)+(436.81)+(396.01)+(118.81)+(47.61)+(118.81)+(50.41)
+(1672.81)+(1376.41)+(1030.41)+(252.81)+(1095.61)+(3.61)+(26.01)+(1374.41)+(320.41)+(18.1)+(252.81)+(252.81)+(1095.61)+(3.61)+(47.61)+(118.81)+(50.41)+(4.41)+(193.21)+(906.01)+(488.41)+(1451.61)+(222.01)+(1288.81)/850.9=
=26367.97/48
σ² = 549.33

DESVIACIÓN

N