Pedeefe
Páginas: 3 (726 palabras)
Publicado: 7 de julio de 2011
Student: You should work the problem completely before referring to the solution.
CHAPTER 2
Solutions included for problems 1, 4, 7, 10, 13, 16, 19, 22, 25,28, 31, 34, 37, 40, 43, 46, 49, 52, 55, 58, 61, 64, 67, 70, 73, 76, 79, and 82
2.1 1. (F/P,8%25) = 6.8485; 2. (P/A,3%,8) = 7.0197; 3. (P/G,9%,20) = 61.7770;
4. (F/A,15%,18) = 75.8364;5. (A/P,30%,15) = 0.30598
2.4 P = 600,000(P/F,12%,4)
= 600,000(0.6355)
= $381,300
2.7 P = 75(P/F,18%,2)
= 75(0.7182)
= $53.865 million2.10 P = 162,000(P/F,12%,6)
= 162,000(0.5066)
= $82,069
2.13 P = 1.25(0.10)(P/F,8%,2) + 0.5(0.10)(P/F,8%,5)
= 0.125(0.8573) + 0.05(0.6806)= $141,193
2.16 A = 1.8(A/P,12%,6)
= 1.8(0.24323)
= $437,814
2.19 P = 75,000(P/A,15%,5)
= 75,000(3.3522)
= $251,415
2.22 P =2000(P/A,8%,35)
= 2000(11.6546)
= $23,309
2.25 (a) 1. Interpolate between n = 32 and n = 34:
1/2 = x/0.0014
x = 0.0007(P/F,18%,33) = 0.0050 – 0.0007
= 0.0043
2. Interpolate between n = 50 and n = 55:
4/5 = x/0.0654x = 0.05232
(A/G,12%,54) = 8.1597 + 0.05232
= 8.2120
(b) 1. (P/F,18%,33) = 1/(1+0.18)33= 0.0042
2. (A/G,12%,54) = {(1/0.12) – 54/[(1+0.12)54 –1}
= 8.2143
28. (a) G = $5 million (b) CF6 =$6030 million (c) n = 12
2.31 (a) CF3 = 280,000 – 2(50,000)
= $180,000
(b) A = 280,000 – 50,000(A/G,12%,5)
= 280,000 – 50,000(1.7746)...
Leer documento completo
Regístrate para leer el documento completo.