PRACTICA ALGEBRA ECUACIONES

1) y=3^x


x y=3^x ( x , y )
-3 =(3)^-3=3/3 1.0000 ( -3,1 )
-2 =(3)^-2=2/3 0.6667 ( -2,0.6667 )
-1 =(3)^-1=1/3 0.3333 ( -1,0.3333 )
0 =(3)^0= 1.0000 ( 0,1 )1 =(3)^1= 3.0000 ( 1,3 )
2 =(3)^2= 9.0000 ( 2,9 )
3 =(3)^3= 27.0000 ( 3,27 )2) y=3^-x
y=3^-x=x/3
x y=x/3 ( x , y )
-3 =-3/3 -1.0000 ( -3,-1 )
-2 =-2/3 -0.6667 ( -2,-0.6666 )
-1 =-1/3 -0.3333 ( -1,-0.3333 )
0 =0/3 0.0000 ( 0,0 )
1 =1/30.3333 ( 1,0.33333 )
2 =2/3 0.6667 ( 2,0.66666 )
3 =3/3 1.0000 ( 3,1 )













3) y=logx^5y=logx^5 =5*log x
x y=5*log x ( x , y )
1 =5 * log 1= 5 * 0= 0.0000 ( 1,0 )
2 =5 * log 2= 5 * 0.3010= 1.5050 ( 2,1.505 )
3 =5 * log 3= 5 * 0.4771= 2.3855 ( 3,2.3855 )
4 =5 *log 4= 5 * 0.6021= 3.0105 ( 4,3.0105 )
5 =5 * log 5= 5 * 0.6990= 3.4950 ( 5,3.495 )
6 =5 * log 6= 5 * 0.7782= 3.8910 ( 6,3.891 )4) y=log 8 * X
y=log 8 *X = log 8 + log X

x y = log 8 + log X ( x , y )
1 =log 8 + log (1) 0.9031 ( 1,0.9031 )
2 =log 8 + log (2) 1.2041 ( 2,1.2041 )
3 =log 8 + log (3) 1.3802 ( 3,1.3802 )4 =log 8 + log (4) 1.5052 ( 4,1.5052 )
5 =log 8 + log (5) 1.6021 ( 5,1.6021 )
6 =log 8 + log (6) 1.6813 ( 6,1.6813 )5) Se tiene la Serie: 4,7,10,13 obtenga el termino 75 de...