Presion Atmosferica

4 TRABAJOS:

1. Determine la presión hidrostática (PH ) y absoluta (PA ) para cada profundidad. (Utilizar H).

PRESION HIDROSTATICA:
Ph=ρ.g.h

GASEOSA:

* H=0,02m
ρ=1025kgm3g=9,8ms2

Ph=1025kgm3x9,8ms2x0,02m

Ph=200,9 Pa

* H=0,04m
ρ=1025Kgm3
g=9,8ms2

Ph=1025Kgm3x9,8ms2x0,04m

Ph=401,8 Pa

* H=0,06
ρ=1025Kgm3g=9,8ms2
Ph=1025Kgm3x9,8ms2x0,06m

Ph=602,7 Pa

* H=0,08
ρ=1025Kgm3
g=9,8ms2

Ph=1025Kgm3x9,8ms2x0,08m

Ph=803,6 Pa

AGUA:

*H=0,02m
ρ=1000kgm3
g=9,8ms2

Ph=1000kgm3x9,8ms2x0,02m

Ph=196 Pa

* H=0,04m
ρ=1000Kgm3
g=9,8ms2

Ph=1000Kgm3x9,8ms2x0,04m

Ph=392 Pa

* H=0,06ρ=100Kgm3
g=9,8ms2
Ph=1000Kgm3x9,8ms2x0,06m

Ph=588 Pa

* H=0,08
ρ=1000Kgm3
g=9,8ms2

Ph=1000Kgm3x9,8ms2x0,08m

Ph=784 PaPRESION ABSOLUTA:

Pabs=Ph+Po

GASEOSA:

* H=0,02m
Ph=200,9Pa
Po=1,013x105Pa

Pabs=200,9Pa+ 1,013x105Pa

Pabs=101500,9Pa

* H=0,04m
Ph=401,8PaPo=1,013x105Pa

Pabs=401,8Pa+ 1,013x105Pa

Pabs=101701,8 Pa

* H=0,06m
Ph=602,7Pa
Po=1,013x105Pa

Pabs=602,7Pa+ 1,013x105Pa

Pabs=101902,7Pa

* H=0,08mPh=803,6 Pa
Po=1,013x105Pa

Pabs=803,6Pa+ 1,013x105Pa

Pabs=102103,6 Pa

AGUA:

* H=0,02m
Ph=196 Pa
Po=1,013x105Pa

Pabs=196Pa+ 1,013x105PaPabs=101496 Pa

* H=0,04m
Ph=392
Po=1,013x105Pa

Pabs=392+ 1,013x105Pa

Pabs=101692Pa

* H=0,06m
Ph=588Pa
Po=1,013x105Pa

Pabs=588Pa+1,013x105Pa

Pabs=101888 Pa

* H=0,08m
Ph=784Pa
Po=1,013x105Pa

Pabs=784Pa+ 1,013x105Pa

Pabs=102084Pa

2. Determine la presión manométrica (Pm ) para cada...