Primer capitulo mott
Conversion factors 1.1 1.2 1.3 1.4 1.5 1.6 1.7 1.8 1.9 1.10 1.11 1.12 1.13 1.14 1.15 1.16 1250 mm(1 m/103 mm) = 1.25 m 1600 mm2[1 m2/(103 mm)2] = 1.6 × 10−3 m2 3.65 × 103 mm3[1 m3/(103 mm)3] = 3.65 × 10−6 m3 2.05 m2[(103 mm)2/m2] = 2.05 × 106 mm2 0.391 m3[(103 mm)3/m3] = 391 × 106 mm3 55.0 gal(0.00379 m3/gal) = 0.208 m3
80 km 103m 1h × × = 22.2 m/s h km 3600 s
25.3 ft(0.3048 m/ft) = 7.71 m 1.86 mi(1.609 km/mi)(103 m/km) = 2993 m 8.65 in(25.4 mm/in) = 220 mm 2580 ft(0.3048 m/ft) = 786 m 480 ft3(0.0283 m3/ft3) = 13.6 m3 7390 cm3[1 m3/(100 cm)3] = 7.39 × 10−3 m3 6.35 L(1 m3/1000 L) = 6.35 × 10−3 m3 6.0 ft/s(0.3048 m/ft) = 1.83 m/s
2500 ft 3 0.0283 m3 1 min × × = 1.18 m3/s min ft 3 60 s
Consistent units in an equation1.17
υ= =
s t
0.50 km 103 m × = 47.2 m/s 10.6 s km
The Nature of Fluids
1
1.18
υ= = υ= = υ= =
2s t
t=
2
s t
1.50 km 3600 s × = 1038 km/h 5.2 s h 1000 ft 1 mi 3600 s × × = 48.7 mi/h 14 s 5280 ft h 1.0 mi 3600 s × = 632 mi/h 5.7 s h (2)(3.2 km) 103 m 1 min 2 = 8.05 × 10−2 m/s2 × × 2 2 km (4.7 min ) (60 s )
1.19
s t
1.20
s t
1.21
a=
=
1.22
2s(2)(13 m) = = 1.63 s a 9.81 m/ s 2 2s t
2
1.23
a=
=
(2)(3.2 km) 103 m 1 ft 1 min 2 ft × × × = 0.264 2 2 2 s km 0.3048 m (60 s ) (4.7 min )
1.24
t=
2s (2)(53 in) 1 ft = × = 0.524 s 32.2 ft/ s 2 12 in a mυ 2 (15 kg)(1.2 m/s ) kg ⋅ m 2 = = 10.8 = 10.8 N ⋅ m 2 2 2 s
2
1.25
KE =
1.26
1 h2 kg ⋅ m 2 mυ 2 (3600 kg) ⎛ 16 km ⎞ (103 m ) ×⎜ × = 35.6 × 103 KE = = ⎟ × 2 2 s22 2 (3600 s ) ⎝ h ⎠ km KE = 35.6 kN ⋅ m
2
2
1.27
mυ 2 75 kg ⎛ 6.85 m ⎞ kg ⋅ m 2 = 1.76 kN ⋅ m KE = = ×⎜ = 1.76 × 103 ⎟ 2 2 2 ⎝ s ⎠ s m= m= 2( KE ) = (2)(38.6 N ⋅ m) ⎛ h 1 km 2 ⎞ 1 kg ⋅ m (3600 s ) ×⎜ × 2 × × ⎟ 2 1 (103 m)2 ⎝ 31.5 km ⎠ s ⋅N h
2 2
2
1.28
υ2
(2)(38.6)(3600) 2 kg = 1.008 kg 2 (31.5) (103 )2 2( KE ) = (2)(94.6 m N ⋅ m) 10−3 N 1 kg ⋅ m 103 g = 37.4 g × × 2 × 2 mNs ⋅N kg (2.25 m/s )
1.29
m=
υ2
1.30
υ=
2( KE ) 2(15 N ⋅ m) 1 kg ⋅ m/s 2 = 1.58 m/s = × m 12 kg N
2
Chapter 1
1.31
υ=
2( KE ) 2(212 m N ⋅ m) 10 −3 N 103 g 1 kg ⋅ m = 1.56 m/s × × × 2 = 175 g mN kg s ⋅N m mυ 2 (1 slug)(4 ft/s ) 2 1 lb ⋅ s 2 /ft = 8.00 lb ⋅ ft = × 2 2 slug 1 h2 (5280 ft ) 2 mυ 2 wυ 2 (8000 lb)(10 mi ) 2 × × = = 2 2 2 g (2)(32.2 ft/s 2 )(h ) 2 (3600 s) 2 mi
1.32
KE =
1.33
KE =
(8000)(10) 2(5280) 2 KE = lb ⋅ ft = 26700 lb ⋅ ft 2 (2)(32.2)(3600)
1.34
KE =
mυ 2 wυ 2 (150 lb)(20 ft/s ) 2 = 932 lb ⋅ ft = = 2 2g (2)(32.2 ft/ s 2 ) = 2(15 lb ⋅ ft) lb ⋅ s 2 = 6.20 slugs = 6.20 2 ft (2.2 ft/ s 2 ) 2(32.2 ft)(38.6 lb ⋅ ft)(h 2 ) 1 mi 2 (3600 s ) 2 × × 2 2 2 2 (5280 ft ) h s (19.5 mi )
1.35
m=
2( KE )
υ2
1.36
w=w=
2 g ( KE )
υ2
=
(2)(32.2)(38.6)(3600) 2 lb = 3.04 lb 2 2 (19.5) (5280) 2 g ( KE ) 2(32.2 ft/ s 2 )(10 lb ⋅ ft) = 4.63 ft/s = 30 lb w 2 g ( KE ) 2(32.2 ft/ s 2 )(30 oz ⋅ in) 1 ft = 5.18 ft/s × = 6.0 oz 12 in w 39 runs 9 innings = 2.49 runs/game × 141 innings game
1.37
υ=
1.38
υ=
1.39
ERA =
1.40
3.12 runs 1 game × × 150 innings = 52 runs game 9 innings 40 runs× 1 game 9 innings = 129 innings × 2.79 runs game
1.41
1.42
ERA =
49 runs 9 innings = 3.59 runs/game × 123 innings game
The Nature of Fluids
3
The definition of pressure 1.43 1.44 1.45 p = F/A = 2500 lb/[π(3.00 in)2/4] = 354 lb/in2 = 354 psi p = F/A = 8700 lb/[π(1.50 in)2/4] = 4923 psi
p= 12.0 kN 103 N (103 mm ) 2 N F = × × = 2.72 × 106 2 = 2.72 MPa 2 2 A π (75 mm ) / 4 kNm m F 38.8 × 103 N (103 mm ) 2 N = × = 30.9 × 106 2 = 30.9 MPa 2 2 A π (40 mm ) / 4 m m F 6000 lb = 119 psi = A π (8.0 in ) 2 / 4 F 18000 lb = 3667 psi = A π (2.50 in ) 2 / 4 20.5 × 106 N π (50 mm ) 2 1 m2 = 40.25 kN × × 2 4 (103 mm) 2 m
1.46
p=
1.47
p=
1.48
p=
1.49
F = pA =
1.50
F = pA = (6000 lb/ in 2 ) π [2.00 in ]2 / 4 p= D=
(
)
= 18850 lb
1.51
F...
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