Problema de la moneda

Estadística

Contamos con una moneda, la cual lanzamos 10 veces en donde podemos obtener 1024 posibles resultados, Águila o Sol.

A continuación se muestra el desarrollo de distribuciónbinomial.

P=1/2
Q=1/2
N=10
μ=n.p=5
δ= n.p.q=2.5

F(0)=10C0 (1/2)^0(1/2)^10=1/1024
F(1)=10C1(1/2)^1 (1/2)^9=10/1024=5/512
F(2)=10C2(1/2)^2(1/2)^8= 45/1024=45/1024
F(3)=10C3(1/2)^3(1/2)^7=120/1024=15/128
F(4)=10C4 (1/2)^4(1/2)^6=210/1024=105/512
F(5)=10C5 (1/2)^5(1/2)^5=252/1024=63/256
F(6)=10C6 (1/2)^6(1/2)^4=210/1024=105/512
F(7)=10C7 (1/2)^7(1/2)^3=120/1024=15/128
F(8)=10C8(1/2)^8(1/2)^2=45/1024=45/1024
F(9)=10C9 (1/2)^9(1/2)^1=10/10245/512
F(10)=10C10 (1/2)^10(1/2)^0=1/1024

| X |10CX |F(X) |XF(X) |(X-M)^2F(x) |(x-m)^2 |
|0 |1 |1/1024 |0 |25/1024 |25 |
|1 |10|10/1024 |10/1024 |160/1024 |16 |
|2 |45 |45/1024 |90/1024|405/1024 |9 |
|3 |120 |120/1024 |360/1024 |480/1024 |4 |
|4|210 |210/1024 |840/1024 |210/1024 |1 |
|5 |252 |252/1024 |1260/1024|0 |0 |
|6 |210 |210/1024 |1260/1024 |210/1024 |1 |
|7|120 |120/1024 |840/1024 |480/1024 |4 |
|8 |45 |45/1024 |360/1024...