Psoa Moral

>> g=tf(3,conv([5 1],conv([3 1],[1 1])))

Transfer function:
3
-------------------------
15 s^3 + 23 s^2 + 9 s + 1

>> step (g)
>> t35=.35*3 t35 = 1.0500>> t85=.85*3 t85 = 2.5500
>> ginput(2)
ans = 5.8724 1.0494
14.5722 2.5494
>> t=0:1:35

t = Columns 1 through 27
0 1 2 3 4 56 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26
Columns 28 through 36
27 28 29 30 31 32 33 34 35>> T1=3*(1-exp(-(t-3.4088)/5.8288))
T1 = Columns 1 through 16
-2.3840 -1.5352 -0.8202 -0.2180 0.2894 0.7167 1.0767 1.3799 1.6353 1.8504 2.0317 2.18432.3129 2.4212 2.5125 2.5893
Columns 17 through 32
2.6541 2.7086 2.7546 2.7932 2.8258 2.8533 2.8764 2.8959 2.9123 2.9261 2.9378 2.9476 2.9559 2.96282.9687 2.9736
Columns 33 through 36 2.9778 2.9813 2.9842 2.9867
>> hold on
>> plot(t,T1)
>> plot(t,T1)

>> g=tf(3,conv([5 1],conv([3 1],[1 1])))Transfer function:
3
-------------------------
15 s^3 + 23 s^2 + 9 s + 1

g=tf(3,conv([5 1],conv([3 1],conv([1 1],[1 0]))))

Transfer function:
3---------------------------
15 s^4 + 23 s^3 + 9 s^2 + s
>> step(g)
Aplicando transformada inversa se tiene
y(t) -75/8*exp(-1/5*t)+27/4*exp(-1/3*t)-3/8*exp(-t)+3
>> T20=0.2*3
T20 =0.6000
>> t60=.6*3
t60 = 1.8000
T20 =0.2*3=0.6000
>> t60=.6*3
t60 =1.8000
>> ginput(2)
ans = 4.2080 0.5934
9.1062 1.8022
>> 4.2080/9.1062 ans = 0.4621Usando la figura 7.7 pag 186
T60/tao=1.7 por lo tanto tao= 5,356588235294118
=0.65
5.35*5.35=28.62
2*.65*5.35=6.955
>> g1=tf(2,[28.62 6.955 1])

Transfer function:
2...