Rdgbedbha

Resumen naturaleza





-Conversion de temperatura

| |de Kelvin |a Kelvin|
|Celsius |°C = K – 273.15 |K = °C + 273.15 |
|Fahrenheit |°F =( 9/5 K ) – 459.67 |K = 5/9 ( °F + 459.67 ) |


| |de Celsius |a Celsius|
|Fahrenheit |°F = ( 9/5 °C ) + 32 |°C = 5/9 ( °F – 32) |
|Kelvin|K = °C + 273.15 |°C = K – 273.15 |


| |de Fahrenheit|a Fahrenheit |
|Celsius |°C = 5/9 ( °F – 32) |°F = ( 9/5 °C ) + 32 ||Kelvin |K = 5/9 ( °F + 459.67 ) |°F = ( 9/5 K ) – 459.67 |





























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