Solucion Nutritiva

Lechuga 25 ton ha
Para obtener los porcentajes se utiliza la siguiente formula
160 x 100% 85 x 100 360 x 100 125 x 100 50 x 1002 - x 2 - x 2 - x 1 - x 2 - x
x=1.25 x=2.35 x=0.6%x=0.8 x=0
Quincena | N | P2O5 | K2O | CaO | MgO |
1 | 2 (1.25%) | 2 (2.35%) | 2 (0.6%) | 1 (0.8%) | 0 (0%) |
2 | 8 (5%) | 5 (5.88%) | 10 (2.78%) | 4 (3.2%) | 2(4%) |
3 | 20 (12.5%) | 12 (14.12%) | 48 (13.4%) | 15 (12%) | 3 (6%) |
4 | 20 (12.5%) | 12 (14.12%) | 48 (13.4%) | 15 (12%) | 5 (10%) |
5 | 55 (34.37%) | 27 (31.77%) | 126 (35%) | 45 (36%)| 20 (40%) |
6 | 55 (34.37%) | 27 (31.77%) | 126 (35%) | 45 (36%) | 20 (40%) |
| 160 | 85 | 360 | 125 | 50 |

160 - 25 ton Se necesita 256 kg ha-1 de N para 40 ton ha-1
x -40 ton 30 m2 - 0.768 kg = 768 gr N

85-25 ton 136 kg ha-1 de P2O5 para 40 ton ha-1
x - 40 ton 30 m2 - 0.408 kg = 408 gr P2O5360-25 ton 576 kg ha -1 de k2O para 40 ton ha-1
x - 40 ton 30 m2 - 1.728 kg de K2O

125-25 ton 200 kg ha-1 de CaO para 40 ton ha-1
x-4030m2 – 0.6 kg = 600 gr CaO

50-25 80 kg ha-1 de MgO para 40 ton
X-40 30m2 - 0.24 kg= 240 gr MgNitrogeno Fosforo Potasio Calcio
768 gr-100% 408 gr-100% 1728 gr-100% 600 gr-100%
X-12.5 %X-14.12 X-13.4 X-12
X=96 gr N X=57.6 P2O5 X=231.6 gr K2O X=72 gr Ca O...