Transformadores Para Rectificacion

Atlas – Hoja N°24-a – Transformadores para rectificación. – Rectificador de media onda
Potencia de tipo: 1 ST = ⋅ ( S 1 + S 2) 2 Valor medio de la tensión rectificada:

Udc

⋅

2π = m

+π / m

−

∫U π
/m

2 max

⋅ cos x ⋅ dx
+π / m −π / m

U dc =

sen π/m sen π/m =U2⋅ 2 ⋅ Udc = U 2 max ⋅ π /m π /m
Valor medio de lacorriente (carga R):

1 ⋅ sen x 2π / m

⋅ U 2 max

Idc = I 2 max ⋅

sen π/m sen π/m = I2 ⋅ 2 ⋅ π /m π /m
2π

Corriente Eficaz secundaria (c/dev.):

I2 =

1 ⋅ 2π2 ∫ Ix ⋅ dx =

0

1 2π 2 ⋅ I dc 2π m

I2 =

Idc m
1 2π 2 ⋅ [( 3 I dc 2π m

Corriente Eficaz primaria(c/devan.):

I1 =

)

2

+ ( 1 I dc 3

)

2
⋅2]

I1 =

1 2 2 2 ⋅ Idc = ⋅ Idc m 3 3⋅ m
π/m

Parámetros Rectificador de media onda (m=3):

U 2 = Udc ⋅

= 0.855 ⋅Udc 2 ⋅ sen π/m Idc Idc I2 = = = 0.577 ⋅ Idc m 3S 1 = 3 ⋅ U 1 ⋅ I 1 = 3 ⋅ U 2 ⋅ I 1 = 1.209 ⋅ Udc ⋅ Idc
ST =

S 2 = 3 ⋅ U 2 ⋅ I 2 = 1.481⋅ Udc ⋅ Idc

ST = 1.345 ⋅ Udc ⋅ Idc
Factor de utilización:

1 1 ⋅ ( S 1 + S2) = (1.481 + 1.209) ⋅ Udc ⋅ Idc 2 2

KT =

KT =

Udc ⋅ Idc = 0.744 1.345 ⋅ Udc ⋅ Idc

Udc ⋅ Idc ST

Hoja N°24-b – Transformadores para rectificación. –Rectificador de onda completa (m=6)
Valor medio de la tensión rectificada:

Udc = 3 ⋅ U 2 ⋅ 2 ⋅

sen π/6 π /6

Udc = 2.34 ⋅ U 2
Valor medio de la corriente:

Idc = I 2 ⋅sen π/6 2⋅ π /6

Corriente Eficaz secundaria (c/dev.):

I2 =

1 2π 2 ⋅2⋅2 I dc = 2π m

=

2 ⋅ Idc 6

I 2 = 0.817 ⋅ Idc
Potencia secundaria y primaria total:S2 = 3 ⋅U 2 ⋅ I 2 =
Udc = 3⋅ ⋅ 0.817 Idc 2.34

S 2 =1.05⋅ Udc ⋅ Idc
S 2 = S1 = ST = 1.05⋅ Udc ⋅ Idc
Factor de Utilización:

KT =

Udc ⋅ Idc 1 = = 0.955 ST 1.05