Vector de fuerza
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1. The above figure shows sevencharges. Determine the direction of the total force on the charge at the origin due to all the other charges. Into which quadrant does the total force vector point?Use the right diagram to draw the individual forces (Choose A, B, C or D).
A
| ¡Correcto! Ahora mostrando respuesta de la Computadora arriba.
Su recibo es163-7697 | |
2. The figure below shows two charges. Calculate the magnitude of the electric field at point P.
Q1 = - 1.70 μC Q2 = - 1.40 μC d1 = 1.10 m d2 =1.80 m
8.75×103 V/m
| ¡Correcto! Ahora mostrando respuesta de la Computadora arriba.
Su recibo es 163-1386 | |
| E1=kQ1/r12E2= la misma mierda qE1Etotal=E1-E2Find the field of Q2 on P, and then set the direction as [left] since that is the direction of the field lines.
Find the field of Q1 on P, set it as[right] since that is the direction of the field lines.
Vector addition. Since the directions are opposite, subtract one from the other.
To find the fields, use yourequation
E=kq/r^2 | |
3. Calculate the size of the force on a charge Q = + 1.70 muC placed at P due to the two charges from the previous problem.
1.49×10-2 N| ¡Correcto! Ahora mostrando respuesta de la Computadora arriba.
Su recibo es 163-8734 |
| Esta parte es como la segunda, solo q en vez de tener un
puntoP, tienes esta carga+. Aqui te pide la Fuerza, (F=Eq),
utilizamos el valor E de la segunda parte y el valor q+
dado. Eso es todo. attCas |
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