Análisis Dc Q1

ANÁLISIS DC Q1
VTH = (Vcc)(R2)R1+R2
VTH =(-9V)(1K)10K+1K = 0,818[V]
RTH = R1 || R2 = 0,909KΩ
1) VCC – IDR1 – VDS = 0
2) VTH – VGS = 0
VGS = VTH =–0,818[V]
3) ID =IDSS1- VgsVp2
ID= (1,63mA) 1- (-0,818)(-2)2
IDQ = 0,569mA
DE 1) DESPEJO VDS
VDS = VCC – IDR1
VDSQ = 9V – (0,569mA)(1KΩ)VDSQ = 8,431[V]
VDS CODO SAT = |VP| – |VGS |
VDS CODO SAT = |– 2| – |– 0,818| = 1,182[V]
VDSQ > VDS CODO SAT ZONA LINEAL
gm = 2Idss|Vp|1- VgsVp = 0,963mƱ

ANÁLISIS DC Q2
1) VCC – IBR4 – VBE = 0
IBQ =9V-0.71M = 8,3µA
ICQ = β IB = 1,162mA
IEQ = (β+ 1) IB = 1,1703mA
2) VCC –R5IC – VCE =0
VCEQ = 9V – (4,7KΩ) (1,162mA)=3,5386[V] ZONA LINEAL
hie = 26mvIb = 3,132KΩ

ANÁLISIS AC
FRECUENCIAS MEDIAS
AV = VxVi * V0Vx
AV = –hie1K1MgmVgsVgs * – 4,7kΩ||330Ωβibhieib
AV = – (3,132 KΩ || 1 KΩ|| 1M)(0,963mƱ) * – 4,7kΩ||330Ω(140)3,132KΩ
AV = 10.04
FRECUENCIAS BAJAS
FLI = 12ΠZiCi ;Zi= R1 || R2 = 0,909 KΩ
FLI = 12Π(0,909KΩ)(10µF) = 17,5HZ
FLA = 1 2ΠZaCa ; Za=R4= 1M
FLA= 12Π(1M)(10µF) = 0,016HZ
FLO = 1 2ΠZoCa ; Zo= R5 + R6 = 5,03 KΩ
FLO= 1 2Π(5,03kΩ)(10µF) = 3,164HZ
FRECUENCIAS ALTAS
AM1 =–hie1K1MgmVgsVgs = – 0,729
AM2 =– 4,7kΩ||330Ωβibhieib = – 13,78
CMLI = CGD |1 – AV|= (2PF)|1– (–0,729)|=3,458PF
CMLO = CGD |1 –1/ AV|= (2PF)|1 + 1/0,729|= 4,743PF
CMCI =CBC |1 – AV|= (1PF)|1–(– 13,78)|= 14,78PF
CMCO = CBC |1 –1/ AV|= (1PF)|1 + 1/13,78|= 0,927PF
CMTI = CWI + CMLI + CGS
CMTI = 3,458PF + 5PF + 4PF= 12,458PF