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Publicado: 26 de marzo de 2013
FORMULARIO OFICIAL PARA CERTAMENES
Óptica Geométrica
n1λ1 = n2 λ 2
n = c/v ;
Constantes
c = 3 ⋅ 108 [m / s] ; e ≈ 1,6 ⋅ 10 − 1 9 [C]
9
2
n1 sen θ1 = n2 sen θ 2
2
k c = 1 4πε0 =9, ⋅ 10 [Nm / C ]
e2 4πε0 = 1,44[eV ⋅ nm] ; µ0 = 4π ⋅ 10 − 7 [N / A 2 ]
h = 6,6 ⋅10
−34
[J ⋅ s] = 4,1⋅10
− 15
θr = θ1
;
n1 n2 n2 − n1
+
=
,
s s'
R
111
+=
s s' f
f = R/ 2 : espejos
[eV ⋅ s]
1
1
1
= ( n − 1)
−
: lentes
R1 R2
f
= h / 2π
h ⋅ c = 1240 [eV ⋅ nm] ;
DE FIS 140
NA = 6,0 ⋅10 2 3 [m ol− 1 ]
−
k B = 1,38 ⋅10 − 2 3 [J/ K] = 1/ 12000[eV / K]
1[eV] = 1,6 ⋅10
−19
1[u] = 1,66 ⋅10
1[fm] = 10
− 15
[kg] = 931,5 MeV / c 2
L
E
c = 197 [MeV ⋅ fm]
[m]
dp
dt
+
[J]
− 27
Físicaclásica
Fn eta =
Adelante
+
; p = mv
(
Óptica Ondulatoria
mgh
1
U = kx 2
2
q i ∆ V
)
()
∫ B ⋅ dA = 0
;
0
Dos fuentes en fase:
φ ; φ = k d senθ
I = I0 cos2
2
m λ : m áxim os
dsen θ =
1
m + 2 λ : m ínim os
Ecuaciones de Maxwell
∫ E ⋅dA = Q / ε
−
v
R
; ac =
p2
1
K = m v2 =
; E = K+U
2
2m
F = qE + v×B
Atrás
2
sen α + sen β = 2⋅ sen [(α +β)/2]⋅ cos [(α −β)/2]
d
∫ E ⋅ ds = − dt φ
;
B
φE =
∫ E ⋅dA
;
w E = ε ⋅ E2 / 2
∫ B ⋅ ds = µ I + µ ε
0
00
d
φ
dtE
2
sen β / 2
Difracción una rendija : I = I0
β/2
β = k a sen θ ; a sen θ = m λ : m ínim os.
w B = B2 / 2µ0
Onda electromagnética
∂ 2E y
∂ x2
2
1 ∂ Ey
= 2⋅
v
∂ t2
ERed de difracción: dsen θ = m λ : m áxim os.
k
S = ExB / µ0
B
2
∂ 2B z
1 ∂ Bz
= 2⋅
∂ x2
v
∂t2
;
v=
2
sen N φ / 2 ; φ = k d sen θ
sen φ / 2
I = I0
∫ B⋅dA
φB =
Interferencia N rendijas:
1
εµ
Polarización:
Resolución:
I = I0 cos2 α
D sen θ = 1,22λ
E y (x, t) = E0 cos(k x − ω t)
B z (x,t) = B0 cos(k x − ω t)
B0 = E0 / v ;...
Óptica Geométrica
n1λ1 = n2 λ 2
n = c/v ;
Constantes
c = 3 ⋅ 108 [m / s] ; e ≈ 1,6 ⋅ 10 − 1 9 [C]
9
2
n1 sen θ1 = n2 sen θ 2
2
k c = 1 4πε0 =9, ⋅ 10 [Nm / C ]
e2 4πε0 = 1,44[eV ⋅ nm] ; µ0 = 4π ⋅ 10 − 7 [N / A 2 ]
h = 6,6 ⋅10
−34
[J ⋅ s] = 4,1⋅10
− 15
θr = θ1
;
n1 n2 n2 − n1
+
=
,
s s'
R
111
+=
s s' f
f = R/ 2 : espejos
[eV ⋅ s]
1
1
1
= ( n − 1)
−
: lentes
R1 R2
f
= h / 2π
h ⋅ c = 1240 [eV ⋅ nm] ;
DE FIS 140
NA = 6,0 ⋅10 2 3 [m ol− 1 ]
−
k B = 1,38 ⋅10 − 2 3 [J/ K] = 1/ 12000[eV / K]
1[eV] = 1,6 ⋅10
−19
1[u] = 1,66 ⋅10
1[fm] = 10
− 15
[kg] = 931,5 MeV / c 2
L
E
c = 197 [MeV ⋅ fm]
[m]
dp
dt
+
[J]
− 27
Físicaclásica
Fn eta =
Adelante
+
; p = mv
(
Óptica Ondulatoria
mgh
1
U = kx 2
2
q i ∆ V
)
()
∫ B ⋅ dA = 0
;
0
Dos fuentes en fase:
φ ; φ = k d senθ
I = I0 cos2
2
m λ : m áxim os
dsen θ =
1
m + 2 λ : m ínim os
Ecuaciones de Maxwell
∫ E ⋅dA = Q / ε
−
v
R
; ac =
p2
1
K = m v2 =
; E = K+U
2
2m
F = qE + v×B
Atrás
2
sen α + sen β = 2⋅ sen [(α +β)/2]⋅ cos [(α −β)/2]
d
∫ E ⋅ ds = − dt φ
;
B
φE =
∫ E ⋅dA
;
w E = ε ⋅ E2 / 2
∫ B ⋅ ds = µ I + µ ε
0
00
d
φ
dtE
2
sen β / 2
Difracción una rendija : I = I0
β/2
β = k a sen θ ; a sen θ = m λ : m ínim os.
w B = B2 / 2µ0
Onda electromagnética
∂ 2E y
∂ x2
2
1 ∂ Ey
= 2⋅
v
∂ t2
ERed de difracción: dsen θ = m λ : m áxim os.
k
S = ExB / µ0
B
2
∂ 2B z
1 ∂ Bz
= 2⋅
∂ x2
v
∂t2
;
v=
2
sen N φ / 2 ; φ = k d sen θ
sen φ / 2
I = I0
∫ B⋅dA
φB =
Interferencia N rendijas:
1
εµ
Polarización:
Resolución:
I = I0 cos2 α
D sen θ = 1,22λ
E y (x, t) = E0 cos(k x − ω t)
B z (x,t) = B0 cos(k x − ω t)
B0 = E0 / v ;...
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