Inegneiro

1. ^KCl = 149.23 – 2.992 (C) 12 + 58.74 x 10-3 (C) Log(C) + 22.18 x 10-3 (C)

* Con 0.1 de concentración
^KCl 0.1 = 149.23 – 2.992 (0.1) 12 + 58.74 x 10-3 (0.1) Log (0.1) + 22.18x 10-3 (0.1)
^KCl 0.1 = 149.0804 + (- 5.874 x 10-3) + 2.218 x 10-3
^KCl 0.1 = 149.0767

^KCl 0.1 = 149.0767



* Con 0.01 de concentración
^KCl 0.01 = 149.23 – 2.992(0.01) 12 + 58.74 x 10-3 (0.01) Log (0.01) + 22.18 x 10-3 (0.01)
^KCl 0.01 = 149.21 + (-1.1748 x 10-3) + 2.218 x 10-4
^KCl 0.01 = 149.2090

^KCl 0.01 = 149.2090


* Con 0.001de concentración
^KCl 0.001 = 149.23 – 2.992 (0.001) 12 + 58.74 x 10-3 (0.001) Log (0.001) + 22.18 x 10-3 (0.001)
^KCl 0.001 = 149.2285 + (- 1.7622 x 10-4) + 2.218 x 10-5
^KCl 0.001 =149.2283

^KCl 0.001 = 149.2283

2. Hallando K

K = ^M1000 (mhoscm-1)

* Con M = 0.1 y ^ = 149.0767

K = 149.0767* 0.11000 (mhoscm-1)
K = 0.01490767 mhoscm-1
K =0.01490767 mhoscm-1

* Con M = 0.01 y ^ = 149.2090

K = 149.2090* 0.011000 (mhoscm-1)
K = 1.492090 x 10-3 mhoscm-1
K = 1.492090 x 10-3 mhoscm-1

* Con M = 0.001 y ^ = 149.2283

K =149.2283* 0.0011000 (mhoscm-1)
K = 1.492283 x 10-4 mhoscm-1
K = 1.492283 x 10-4 mhoscm-1

3. Hallando C

C = K x 1cm-1Kobs

* Con K = 0.01490767 mhoscm-1 y Kobs = 12.21 mScm

C= 0.01490767 mhoscm-1 x 1cm-112.21 mS/cm
C1 = 1.2209 x 10-3

C1 = 1.2209 x 10-3



* Con K = 1.492090 x 10-3 mhoscm-1 y Kobs = 1.58 mScm

C = 1.492090 x 10-3 mhoscm-1 x1cm-11.58 mS/cm
C2 = 9.4436 x 10-4

C2 = 9.4436 x 10-4



* Con K = 1.492283x 10-3 mhoscm-1 y Kobs = 151.6 μScm

151.6 μScm x 1mS1000μS = 0.1516mS

C = 1.492283 x 10-3mhoscm-1 x 1cm-1151.6 mS/cm
C3 = 9.8435 x 10-5

C3 = 9.8435 x 10-5




Promedio = C1+C2+C3 3

Promedio = 1.2209 x10-3+9.4436 x10-4+9.8435 x10-5 3

Promedio = 7.250 x 10-4