pratctica termo

V1
V2
X1
X2
n(liq)
Tem
n(cond)
Y1
Y2
0
25
0
1
1.3303
59
1.3298
0.003567
0.9964
4.51
20.49
0.1
0.9
1.3527
57
1.3663
0.17828
0.82172
8.28
16.72
0.2
0.8
1.3691
541.3916
0.37296
0.62704
11.48
13.52
0.3
0.7
1.3818
53
1.4044
0.4944
0.5056
14.22
10.78
0.4
0.6
1.3919
51
1.4056
0.50657
0.49343
16.65
8.35
0.5
0.5
1.4043
48
1.4154
0.611080.38892
18.73
6.27
0.6
0.4
1.4155
47
1.4186
0.64716
0.35284
20.57
4.43
0.7
0.3
1.4265
47
1.4220
0.6865
0.3135
22.21
2.75
0.8
0.2
1.4327
47
1.4269
0.74524
0.25476
23.68
1.320.9
0.1
1.4400
48.5
1.4303
0.78728
0.21272
25
0
1
0
1.4420
-----
1.4420
0.9403
0.0597


Tem C
Tem K
59
332.15
57
330.15
54
327.15
53
326.15
51
324.15
48
321.15
47320.15
47
320.15
47
320.15
48.5
321.15
51
324.15



5.-Calculando las presiones de saturación a la T corregida mediante la ecuación de Antoine.



sustancia
A
B
C
Metanol
18.58753626.55
-34.29
Cloroformo
15.9732
2696.79
-46.16


Psat1,1= ==609.2015mmHg
Psat1,2= ==561.0692mmHg
Psat1,3= ==494.8622mmHg
Psat1,4= ==474.3050mmHg
Psat1,5= ==435.3347mmHg
Psat1,6===381.9426mmHg
Psat1,7= ==365.4191mmHg
Psat1,8= ==365.4191mmHg
Psat1,9= ==365.4191mmHg
Psat1,10= ==381.9426mmHg
Psat1,11= ==435.3347mmHg




Psat2,1 =472.40403
Psat2,2 =442.05141
Psat2,3 =399.43099Psat2,4 =385.97135
Psat2,5 =360.13094
Psat2,6 =323.96461
Psat2,7 =312.57408
Psat2,8 =312.57408
Psat2,9 =312.57408
Psat2,10 =323.96461
Psat2,11=360.13094









Psat1
609.2015435.3347
494.8622
474.3050
435.3347
381.9426
365.4191
365.4191
365.4191
381.9426
561.0692

6. Calcular el coeficiente de actividad (γ) con la ecuación:

P=585 mmHg
=2.41236906
=0.982468γ1
γ2
Indeterminado.
0.982468
2.41236906
0.96917859
2.03173843
0.99614405
2.11125983
1.01650292
1.64626109
1.18370535
1.55716626
1.24293973
1.39699983
1.44496106
1.2355096
1.77218068...