Alejandro

 Alejandro Rodríguez
C.I: 18.114.970
PROBLEMA 1
Calcular los esfuerzos para una viga simplemente apoyada de 40m de luz cuando se somete a la acción de una fuerza de pretensióninicial de 183420 kg y a la acción las siguientes cargas:

WPP:1850 kg/ ml
Wsc: 2370 Kg/ ml
Yconcreto: 2500 Kg/m3
r: 12 cms
a) Esfuerzos
b) diagrama de esfuerzos

A1= 60 x 20 = 1200 cm2
A2= 16 x 10/3 =53.33 cm2
A3= 16 x 10/3 = 53.33 cm2
A4= 106 x 20 = 2120 cm2
A5= 10 x 10/2 = 50 cm2
A6= 10 x 10/2 = 50 cm2
A7= 40 x 20 = 800 cm2




E.N.= 67.057 m

d1= 67.057 – 10 = 57.05m
d2= 67.057 – 24.8 =42.2m
d3= 67.057 – 24.8 = 42.2 m
d4= 67.057 – 73 = 5.95m Ya=78.943
d5= 67.057 – 119.3 = 52.2 m Yb= 67.057
d6= 67.057 – 119.3 = 52.2 m
d7= 67.057 – 136 =68.95 m

I1= 60 x (20)3/12 + 1200 x (57.05)2= 3945643 m3
I2= (10)3 x 16/5 + 53.33 x (42.2)2 =98172.197 m3
I3= (10)3 x 16/5 + 53.33 x (42.2)2 = 98172.197m3
I4= 20 x (106)3/12 + 2120 x (5.95)2 = 2060079.96m3
I5= (10)3 x 10/36 + 50 x (52.2)2 =136519.77m3
I6= (10)3 x 10/36 + 50 x (52.2)2 = 136519.77m3
I7= 40 x (20)3/12 + 800 x (68.95)2 = 3829948.66m3



a Esfuerzos Externos: Ya=78.943, Yb= 67.057
Esfuerzos por peso propio
Mpp= Wppx L2/8 = 1850 x (40)2/8 = 370000

Fapp = Mpp x Ya/I Fapp = 370000 x78.943 /10305055.55=
Fapp=2.83
Fbpp = Mpp x Yb/I Fbpp = 370000 x67.057 / 10305055.55 =
Fbpp=2.40

Esfuerzos por sobre carga:Msc= Wsc x L2/8 = 2370 x (40)2/8 = 474000
Msc= 474000

Fasc = Msc x Ya/I Fasc = 474000 x78.943 /10305055.55 =
Fasc=3.63
Fbsc = Msc x Yb/I Fasc = 474000 x67.057 /10305055.55 =
Fbsc=3.08

bEsfuerzos Internos:
e = E.N. – r = 67.057– 12 = 55.057

Fapret = Pri/A + Pri x e x Ya/I= 183420/ + 183420 x55.057 x78.943 /10305055.55 =
Fapret = 34.968
Fbpret = Pri/A + Pri x e x Yb/I= -183420/-183420 x 55.057 x 67.057/10305055.55 =
Fbpret = -108.121

c Esfuerzos Totales:

Fatotales = Fapp + Fasc + Fapret = 2.83+ 3.63 + 34.968 =
Fatotales= 41.428
Fbtotales = Fbpp + Fbsc + Fbpret = 2.40+...