aporte individual trabajo colaborativo 1 algebra lineal

1.
1.1. |u| = 2; θ = 120° → ȗ = (-1, 1.7)
|v| = 3; θ 60° → v = (1.5, 2.6)
ȗ-v = (-1, 1.7) – (1.5, 2.6)
R// ȗ-v = (2.5, -0.9)

1.2
v-ȗ = (1.5, 2.6) – (-1, 1.7)R// v-ȗ = (2.5, 0.9)

1.3
5v -2ȗ = 5(1.5, 2.6) -2 (-1, 1.7) = (7.5, 13) – (-2, 3.4)
R// 5v - 2ȗ = (9.5, 9.6)



2.1 ȗ = 2i+9j v = -6i-4j
ȗ.v = (2, 9) (-6, -4) =(2)(-6) + (9)(-4) = - 12 – 36
ȗ.v = -48
|u| = √((2) )2+(9)2 = √(4+81)
|u| = √85
|v| = √((-6))2+(-4)2 = √(36+16)
|v| = √52

Cosθ = u.v/|u||v|
Cosθ= -48/√82. √52 = -48/√4420θ = cos-1-48/√4420 = cos-1-48/66.5
θ= cos-1 -0.72
R// θ= 136.05°

2.2
v.u = (-1, -4) (-7, -5) = (-7, -5) = (-1)(-7) + (-4)(-5) = 7 +20
v.u = 27
|v| = √((-1)2+(-4))2 = √(49+25)
|v| =√17
|u| = √((-7))2+(-5)2 = √(49+25)
|u| = √74
Cosθ= 27/√17. √25
Cosθ= 27/√1258 = 27/35.5
θ= cos-1 0.76
R// θ = 40.5°




8 5 3 1 0 0F1= 1/8 f1 7 -2 -1 0 1 0
0 1 -3 0 0 1

1 5/8 3/8 1/8 0 0F2= -7 f1+f2 7 -2 -1 0 1 0
0 1 -3 0 0 1

1 5/8 3/8 1/8 0 0F2= -8/51-f2 0 -51/8 -28/8 -7/8 1 0
0 1 -3 0 0 1

1 5/8 3/81/8 0 0
F1= -5/8f2+f1 0 1 29/51 7/51 -8/51 0
0 1 -3 0 0 11 0 1/51 2/51 5/51 0
F3= -1f2+f3 0 1 29/51 7/51 -8/51 0
0 1 -3 0 0...