Cinetica Quimica

1.
Vox = Vo* CosƟ
Vox = 75m/s *CosƟ = 75m/s
Voy = 75m/s*Sen0° = 0 m/s
y=y0+V0yt-12gt2
150m=0m+0m/s* t-12gt2
12gt2= 150m
T= ( 2*150m)^1/2
g^1/2
t= 5.53s

2.
V=d/t
V= 220/5.53
=39.7m/s
Para armar la cama deberásalir 15 segundos antes y armarla en el punto donde caerá el coyote.
3.
En t = 5s
Y = -12gt2
Y=-12(9.8m/s2)(5s)2 = -122.5m
X = Vo* CosƟ t
X= 75m/s(5s)= 375m
r=(375m)2+(-122.5)2 = 394m

En t = 3s
Y=-12(9.8m/s2)(3s)2 = -44.1m
X= 75m/s(3s)= 225m
r=(225m)2+(-44.1m)2 = 229m

En t= 1s
Y=-12 (9.8m/s2)(1s)2 = -4.9m
X= 75m/s(1s)=75m
r=(75m)2+(-4.9m)2 = 75.15m

4.
t= 5s Voy= 0m/s
Vy= Voy – gt
Vy = (-9.8m/s2)(5s)
Vy =-49m/s
t= 3s
Vy = (-9.8m/s2)(3s)
Vy = -29.4m/s

t= 1s
Vy = (-9.8m/s2)(1s)
Vy = -9.8m/s

Luego v=Vy 2+Vx 2como Vx es constante durante la caída, luego Vx = 75m/s

t= 5s v=(75m/s) 2+(- 4.9m/s)2 = 89.5 m/s
t= 3s v=(75m/s)2+(- 29.4m/s)2 = 80.5 m/s
t= 1s v=(75m/s) 2+(- 9.8m/s)2 = 75.6 m/s

5.
La aceleración será la de la gravedaday = -9.8m/s2 en t= 5s, t=3s y t=1s
ay = -9.8m/s2
ax = 0m/s2
a= ay 2+ax 2
a= ( -9.8) 2+0 2
a= 9.8m/s2