Columna en flexocompresion
2
rec := 2 ⋅ cm de := 10 ⋅ mm db := 18 ⋅ mm db 2 d = 46.1 cm I :=h⋅b
3
12
Ag := b ⋅ h
Iy := Iy = 5.208 × 10
−3
b⋅h
4
3
12
Ix :=
h⋅b
3
12
−3
m
Ix = 5.208 × 10
m
4
fy :=4200 ⋅
kgf cm
2
fc 1000 ⋅ lbf in
2
= 4 ksi
fy 1000 ⋅ lbf in
2
K ⋅L = 60 ksi I Ag
= 42
h − 2 ⋅ rec − 2 ⋅ de − db
= 84 %Amplificación de momento de diseño por esbeltez Po := 0.1 ⋅ fc ⋅ Ag Po = 62.5 tonf Pu Po , 0.7⎟
ϕ := if ⎜ Pu < Po , 0.9 − 0.2 ⋅ E := 15100 ⋅
2
⎛ ⎝
⎞ ⎠
ϕ =0.8 kgf cm
2
kgf cm
2
⋅
fc
kgf cm
2
E = 238751.96
Pc := δ :=
π ⋅ E ⋅ Ix ( K ⋅ L) 1
2
Pc = 3409.13 tonf δ = 1.012
1−
Pu ϕ ⋅ PcMu := δ ⋅ Mu
Mu = 11.19 tonf ⋅ m
USAR DIAGRAMA E4-60.90 Pu Ag Absisa lbf in = 127
2
Ordenada
= 183
Mu Ag ⋅ h
lbf in
2
Cuantíacalculada ρ := 0.01 As := ρ ⋅ Ag
2⎞ 0.5 ⎛ ⎜ 1 + Pu ⋅ cm ⎟ ⋅ 0.53 ⋅ kgf ⋅ fc ⋅ Ag Vc := cm 1.4 ⋅ Ag kgf ⎠ ⎝
As = 25 cm
2 3
Armadura longitudinal
−2Vc = 2.1 × 10 m ⋅ s
4φ18 por cara tonne (30.48)
Separación de estribos s := 20 ⋅ cm Av := if ⎢
⎡ Vu ≥ Vc , ⎛ Vu − Vc⎞ ⋅ s , 3.51 ⋅ kgf ⋅ b ⋅ sAv =0.84 cm2 ⎤ ⎜ ⎟ 2 ⎥ fy ⋅ b 0.85 0.85 ⎝ ⎠ fy ⋅ cm ⎣ ⎦
Armadura de corte E φ10 a 20 (1.57)
tonf := 1000kgf
4
Vc1 :=
fc MPa
⋅b⋅
d 6
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