La Presa

EAD1012030

María Del Rosario Ramírez Castor

[pic]



Formula de la distancia, para obtener el perímetro del “Enroca miento interno”

[pic]



Datos: A= (0,0), B= (10,0), C= (16,30)[pic] = [pic] = [pic]

[pic], [pic]



[pic] = [pic]

[pic]



[pic] = [pic]

[pic] [pic], [pic]



Perímetro es igual a la suma de:
Segmentos _

[pic] , [pic], [pic]Perímetro del enroca miento interno es igual a 74.59 m.





Enroca miento externo, perímetro:



[pic]



Datos: A (20,30), B (27,0), C (37,0)

[pic] = [pic] = [pic]

[pic],[pic]



[pic] = [pic] = [pic]

[pic], [pic]



[pic] = [pic] = [pic]

[pic]



Perímetro es igual a la suma de los segmentos [pic]


P= 75.28 m Enrocamiento Externo.Filtro, su perímetro



[pic]



Datos: A (20,30), B (26,0), C (27,0)

[pic] = [pic] = [pic]

[pic], [pic]



[pic] = [pic] = [pic]

[pic],[pic]



[pic] = [pic] = [pic]

[pic]

Perímetro del filtro es igual a la suma de los segmentos:

[pic]m.

P= 62.39 m.





















Corazón, su perímetro=110.12 m.

[pic]

Datos: A= (16,30), B= (10,0), F= (26,0), G= (20,30)

[pic] = [pic] = [pic] =[pic] ,

[pic]

[pic] [pic] = [pic]

[pic]

[pic] = [pic] = [pic]

[pic], [pic]

[pic]= [pic] = [pic]

[pic]

P1= 81.18 m

Datos de la parte baja del corazón:

C (13, 0), D (16, -4), E(20, -4), H(23,0)

[pic] = [pic] = [pic] =[pic] ,

[pic]

[pic] = [pic] = [pic][pic], [pic]

[pic] = [pic] = [pic]

[pic], [pic]

[pic] = [pic] = [pic]

[pic] . P2= 28.94 m

Perímetro total = 110.12 m.



1.- Enroca miento interno su área = 150 U2Datos: A (0,0), B (10, 0), C (16,30)

[pic]



Enroca miento externo su área = 150 U



Datos: A (20,30), B (27,0), C (37,0)



[pic]









Corazón; su área total =328 U2...