La Segunda Ley De Newton

Páginas: 2 (500 palabras) Publicado: 30 de noviembre de 2012
Tabla 1:
1) Masa en el porta masa (kg)
Caso 1:
m: 0.005 kg
Caso 2:
m + .01 = 0.005 kg + .01 kg = 0.015 kg
Caso 3:
m + .02 = 0.005 kg + .02 kg = 0.025 kg
Caso 4:
m + .03= 0.005 kg + .03 kg = 0.035 kg
Caso 5:
m + .04 = 0.005 kg + .04 kg = 0.045 kg
Caso 6:
m + .05 = 0.005 kg + .05 kg = 0.055 kg
2) mMm+M(Kg)
Caso 1:
0.005 kg(0.4995 kg)0.005kg+0.4995 kg(Kg) = 0.0050 kg
Caso 2:
0.015 kg(0.4995 kg)0.015 kg+0.4995 kg(Kg) = 0.0146 kg

Caso 3:
0.025 kg(0.4995 kg)0.025 kg+0.4995 kg(Kg) = 0.0238 kg

Caso 4:
0.035kg(0.4995 kg)0.035 kg+0.4995 kg(Kg) = 0.0327 kg

Caso 5:
0.045 kg(0.4995 kg)0.045 kg+0.4995 kg(Kg) = 0.0413 kg

Caso 6:
0.055 kg(0.4995 kg)0.055 kg+0.4995 kg(Kg) = 0.0495 kg
3)F= mMm+Mg (N)
Caso 1:
0.005 kg(0.4995 kg)0.005 kg+0.4995 kg(9.8 m/s2) = 0.0485 N

Caso 2:
0.015 kg(0.4995 kg)0.015 kg+0.4995 kg(9.8 m/s2) = 0.1427 N

Caso 3:
0.025kg(0.4995 kg)0.025 kg+0.4995 kg(9.8 m/s2) = 0.2333 N

Caso 4:
0.035 kg(0.4995 kg)0.035 kg+0.4995 kg(9.8 m/s2) = 0.3205 N

Caso 5:
0.045 kg(0.4995 kg)0.045 kg+0.4995 kg(9.8m/s2) = 0.4046 N

Caso 6:
0.055 kg(0.4995 kg)0.055 kg+0.4995 kg(9.8 m/s2) = 0.4855 N
Tabla 2:
E1-E2(E1+E2)2 X 100=
0.507 kg-0.4995 kg(0.507 kg+0.4995 kg)2 x 100 = 1.49 %Tabla 3:
1) Masa del carrito MT (kg)
Caso 1:
m: 0.5 kg
Caso 2:
m + .01 = 0.5 kg + 0.1 kg = 0.6 kg
Caso 3:
m + .02 = 0.5 kg + 0.2 kg = 0.7 kg
Caso 4:
m + .03 = 0.5 kg + 0.3kg = 0.8 kg
Caso 5:
m + .04 = 0.5 kg + 0.4 kg = 0.9 kg
Caso 6:
m + .05 = 0.5 kg + 0.5 kg = 0.1 kg
2) 1MT(Kg-1)
Caso 1:
10.5=2(Kg-1)
Caso 2:
10.6=1.67(Kg-1)
Caso 3:10.7=1.43 (Kg-1)
Caso 4:
10.8=1.25 (Kg-1)
Caso 5:
10.9=1.11 (Kg-1)
Caso 6:
10.1 10 (Kg-1)

Tabla 4:
E1-E2(E1+E2)2 X 100=
0.0882 N-0.098 N(0.0882 N +0.098 N)2 x 100 = 10.5 %
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