Operaciones

Tabla 3. Datos de altura en la tubería de 1 in y 36 in de longitud.
Venturi | Tubería | Q.10-4(m3/s) |
h1 (in H2O) (m) | h2 (in H2O) (m) | h3 (in H2O) (m) | h4 (in H2O) (m) | |
0.0127 | 0.1143 | 0.0952 | 0.0254 | 2.83 |
-0.0254 | 0.1270 | 0.0730 | 0.0857 | 3.47 |
-0.0603 | 0.1428 | 0.0635 | 0.0825 | 4.02 |
0.0539 | 0.1047 | 0.0984 | 0.1016 | 1.989 |
-0.1111 | 0.1619 | 0.0730 |0.0476 | 4.67 |

Q.10-4 (m3/s) (Venturi) |
2.7356 |
3.3501 |
3.9633 |
2.1212 |
4.8088 |

Hr (m) | Pr (Pa) | V (m/s) | Re | f |
0.1016 | 992.9085 | 1.8557 | 2.95*104 | 0.0236 |
0.1524 | 1489.3628 | 2.6886 | 3.62*104 | 0.0225 |
0.2031 | 1984.8398 | 2.2726 | 4.28*104 | 0.0217 |
0.0508 | 496.4542 | 1.4389 | 2.29*104 | 0.0251 |
0.273 | 2667.9531 | 3.2621 | 5.19*104 | 0.0207 |hf teórico (m) | hf experimental (m) | Ht | P | %E |
0.2764 | 0.0697 | -0.0698 | 682.1359 | 7.78% |
0.5532 | 0.0253 | 0.0127 | 248.2271 | 5.42% |
0.3812 | 0.0189 | 0.019 | 185.6817 | 9.50% |
0.1767 | 0.0126 | 0.0032 | 31.2727 | 9.86% |
0.7493 | 0.0031 | -0.0254 | 124.1135 | 9.95% |

Calculo Diferencial de Altura Diferencial de Presión
∆Hr=h2- h1 ∆Pr=∆Hr*φ*ggc∆Hr=0.1143m- 0.0127m=0.1016m φ=996.2 (kg/m3)
∆Hr=0.1270m-(-0.0254)m=0.1524m g=9.81 (m/s2)
∆Hr=0.1428m-(-0.0603m)=0.2031m gc=1.00 (kg*mN*s2)
∆Hr=0.1047m- 0.0539m=0.0508 m ∆Hr=0.1619m-(-0.1111m)=0.273m

∆Pr=0.1016m*996.2 (kg/m3)*9.81 (m/s2)1.00 (kg*mN*s2)=992.9085 Pa
∆Pr=0.1524m*996.2 (kg/m3)*9.81 (m/s2)1.00 (kg*mN*s2)=1489.3628Pa
∆Pr=0.2031m*996.2 (kg/m3)*9.81 (m/s2)1.00(kg*mN*s2)=1984.8398Pa
∆Pr=0.0508m*996.2 (kg/m3)*9.81 (m/s2)1.00 (kg*mN*s2)=496.4542Pa
∆Pr=0.273m*996.2 (kg/m3)*9.81 (m/s2)1.00 (kg*mN*s2)=2667.9531Pa

Regresión Lineal y Cálculo de Caudal
Y=m*x+b = ∆Pr=8.0796*106Q+(-1217.3961)
r=0.9921 b=-1217.3961 m=8.0796*106
Q=992.9085Pa-(-1217.3961)(8.0796*106)=2.7356*10-4 m3/s
Q=1489.3628Pa-(-1217.3961)(8.0796*106)=3.3501*10-4 m3/sQ=1984.8398Pa-(-1217.3961)(8.0796*106)=3.9633*10-4 m3/s
Q=496.4542Pa-(-1217.3961)(8.0796*106)=2.1212*10-4 m3/s
Q=2667.9531Pa-(-1217.3961)(8.0796*106)=4.8088*10-4 m3/s

Calculo de Diámetro interno y Área
DN= 1 in Di= Dext-2t
De la tabla 6.19 del Perry
Dext= 0.0158m t= 1.0160*10-3m
Di= 0.0158m-2(1.0160*10-3m)= 0.0137m

A=D2*π4 A=(0.0137m2)*π4=1.4741*10-4m2

Cálculo de Velocidad
V=QA
V=2.7356*10-4(m3/s)1.4741*10-4m2=1.8557(m/s) V=3.3501*10-4 (m3/s)1.4741*10-4m2=2.2726(m/s)
V=3.9633*10-4(m3/s)1.4741*10-4m2=2.6886(m/s) V=2.1212*10-4(m3/s)1.4741*10-4m2=1.4389(m/s)
V=4.8088*10-4(m3/s)1.4741*10-4m2=3.2621(m/s)

Cálculo de Reynols
Re=4*Qπ*D*ϑ

Re=4*2.7356*10-4 (m3/s)π*0.0137m*8.6*10-7 (m2/s)=2.95*104
Re=4*3.3501*10-4 (m3/s)π*0.0137m*8.6*10-7 (m2/s)=3.62*104
Re=4*3.9633*10-4(m3/s)π*0.0137m*8.6*10-7 (m2/s)=4.28*104
Re=4*2.1212*10-4 (m3/s)π*0.0137m*8.6*10-7 (m2/s)=2.29*104
Re=4*4.8088*10-4 (m3/s)π*0.0137m*8.6*10-7 (m2/s)=5.19*104

Clculo del Factor de Fricción
F=0.00551+20000*ED+106Re13
E= 0.00152*10-3m (tomado del Perry)

F=0.00551+20000*0.00152*10-3m0.0137m+1062.95*10413=0.0236
F=0.00551+20000*0.00152*10-3m0.0137m+1063.62*10413=0.0225F=0.00551+20000*0.00152*10-3m0.0137m+1064.28*10413=0.0217
F=0.00551+20000*0.00152*10-3m0.0137m+1062.29*10413=0.0251
F=0.00551+20000*0.00152*10-3m0.0137m+1065.19*10413=0.0207

Cálculo de hf teórico
hf=f*LD*V22*g L=0.9144m
hf=0.0236*0.9144m0.0137m*1.8557ms22*9.81ms2=0.2764m
hf=0.0225*0.9144m0.0137m*2.6886ms22*9.81ms2=0.5532m
hf=0.0217*0.9144m0.0137m*2.2726ms22*9.81ms2=0.3812mhf=0.0251*0.9144m0.0137m*1.4389ms22*9.81ms2=0.1767m
hf=0.0207*0.9144m0.0137m*3.2621ms22*9.81ms2=0.7493m

Cálculo de Diferencial de Altura de la Tubería
∆Hr=h3- h4
∆Hr=0.0254m-0.0952m=-0.0698m ∆Hr=0.0857m-0.0730m=0.0127m
∆Hr=0.0825m-0.0635m=0.019m ∆Hr=0.1016m-0.0984m=0.0032m
∆Hr=0.0730m-0.1619m=-0.0254m

Cálculo de Diferencial de Presión

∆P=∆Ht*φ*g
∆P=0.0698m*996.2kgm3*9.81ms2=682.1359Pa
∆P=0.019m*996.2kgm3*9.81ms2=185.6817Pa...