Tutorial Scilab

Condición de estancamiento.
π.DpN.d=6
π.36.14=N
N= 7 pernos
Calculo de longitud de pernosL=(1/2)+(1/8)+(7/32)+2(0.0357)=0.9152 in
L=1 in
Calculo de kb
kb=At.Elt=0.0364.(30*106)0.6250=1.7472 Mlbin
Calculo dekm
Ag=Ag totalN
Ag total=π.r02+r12N+π.d24=π(2.252+22)4-7.π1/424=0.4909
Ag=0.49097=0.0701in2km=kg=Ag.EjuntaL=0.0701(23.20*106)1/6=9.76Mlbin
Calculo de C
c=kbkm+kb=1.74729.76+1.74=0.15
Calculo de factor dediseño a fatiga nf
Ptota=PAefectiva del empaque=145.0377*π224=455.6445 lb
Pperno=PtotalN=455.64957=65.092 lbσa=CP2At=0.15*65.0922*0.0364=134.11 psi
Sa=12Se(SutSut2+4SeSe+σi-Sut2-2σiSe)Sa=12*18.6*103(120*103120*1032+4*18.6*10318.6*103+0.75*85*103-120*1032-2*0.75*85*10318.6*103)
Sa=11320.67 psi
nf=Saσa=11320.67134.11=84.41Calculo de factor de diseño fluencia np
σm=CP2At+FiAt=0.15*65.0922*0.0364+0.75*85*103=63884.12 psinp=Spσm+σa=85*10363884.12+134.11=1.32
Calculo de factor de diseño fluencia n0n0=FiP(1-C)=0.75*85*103*0.036465.092(1-0.15)=41.94

Figura 1: Corte transversal de tanque presurizado (todas las cotas en pulgadas)