Formulario derivadas e integrales
u,v,w = expresiones algebraicas; a,b,c,n = constantes
1.
d
dx
c=0
2.
d
dx
x =1
3.
d
dx
=
( u + v + w)
4.
d
dx
( c ⋅ v ) =c ⋅
5.
d
dx
6.d
11. dx
(u ⋅ v) =
d
dx
d
dx
u⋅
d
dx
u+
d
dx
v+
d
dx
w
v
v + v⋅
d
dx
u
d
( v ) = n ( v ) dx v
d
dx ( x )= n ⋅ x
14.
v
d
v −1
=
(sen v )
8.
9.
d
dx
d
dx
d
10. dx
u
v
u
c
v⋅ u −u⋅
d
dx
=
=
v
2
u
c
d
dx
( ln v ) =
=
( tan v )
d
sec v ⋅ dx v
2
d
dx
(sec v ) = sec v ⋅ tan v ⋅
d
− csc
( csc v ) = v ⋅ cot v ⋅ dx v
v
21. dx ( arcsen v ) =
d
2
d
dx
v
d
dx
v=
d
27. dx
2
v
v −1
2
−
d
dx
v
v v −12
d
v ⋅ dx v
d
dx
v
1+ v
( arccsc v ) =
d
26. dx
− csc
( cot v ) =
20. dx
v
v
2
d
dx
d
v
d
18. dx
2
v
1+ v
24. dx ( arccot v ) = −− sen d
( cos v ) = v ⋅ dx v
17. dx
19.
d
dx
d
dx
25. dx ( arcsec v ) =
d
v
d
dx
d
dx
v
1− v
d
d
16. dx
n −1
n
v
d
cos v ⋅ dx v
d
7.( arctan v ) =
dx
d
23.
u
v
d
d
dx
22. dx ( arccos v ) = −
v
u
u
15. dx
n −1
n
u
12. dx
13.
d
dx
d
( a ) =a ⋅ ln a ⋅ dx u
d
d
)
dx ( e = e ⋅dx u
d
d
v
⋅ dx u + ln u ⋅ u
dx ( u ) =⋅ u
d
d
dx
log e
( log v ) =
v
2 v
d
dx v
1− v
2
ELABORÓ: PROF. JESÚS CALIXTO SUÁREZ
Integrales inmediatas
1.
∫ ( du + dv+ dw) = ∫ du + ∫ dv + ∫ dw
11.
∫ csc
2.
∫ a dv = a ∫ dv
12.
v dv
∫ sec v tan =
3.
∫ dx=
13.
− csc
∫ csc v cot v dv = v + C
14.
∫ tan v d
15.
∫
x+C
dv∫v=
v
n
4.
∫
5.
dv
n +1
v dv = v + C
− cot
∫
21.
sec v + C
6.
v
a
23.
cot v dv ln sen v + C
=
ln ( sec v + tan v ) + C
17.
ln a
∫ csc v dv=...
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