# Techumbre

Páginas: 4 (960 palabras) Publicado: 11 de febrero de 2011
DIAGRAMAS FINALES

Tramo A – B

11180. 137 KG-M MA = -909.929¬¬¬¬¬¬ + 11180.137+7053.44(8)-HB(8)=
BHB= 8337.216 KG
7053.4 HB
8M

HA FX= 7053.44-8337.216+ HA(8)=HA= 1283.773 KG

909.929KG

TRAMO C-D MD= -11764.876-10529.7414+HC(8)

10529.7414 KG-M HC= 2786.826 KG
C

HC HD = 2786.826 KG8M

HD
D
11764.867 KG-M

TRAMO E-F

25124.956 KG-M MF= -19062.417 – 25124.956 + HE (8)=
E
HE= 5523.421 KG
HC
8M HF = 5523.421 KG

HD
F
19062.417 KG-M

TRAMOB-C

25M

MB= 683.12 (25) / 2 + 49554.8665- 11184.876 – VC (8) =

VC= 10073.80 KG

FY= VB -683.12(25) + VC=

VB = 7004.2 KG

TRAMO C-E

25M

MC = - 39026.568 + 683.12 (25) / 2+ 25127.2144 – VE (25)=0

VE = 7983.025 KG

FY = VC – 683.12 (25) +7983.025 =

VC = 9094.975 KG

|

TRAMO E –F (MAS CRITICA) PERFIL IR 305 X 226.4

A= 288.4 CM2
5523.421KG
r min = 8.1CM

25124.95 KG -M

8M

19062.417 KG-M

5523.421 KG

fa = P /A = 5523.421 KG / 288.4CM2 = 19.15 KG/ CM2

KL / r min = 0.8 (800 KG/CM2) / 8.1 CM = 79.01

Fa = 1088KG/CM2

fa / Fa = 19.15KG/CM2 / 1088 KG/CM2 = .017

COMO ES MENOR A 1.5 SE CALCULA CON
fa/ Fa + fb/ Fb =1

fb= MC/I = 2512495 KG – CM (15.25CM) = 642.65 KG / CM2

59621 CM4L/ rt = 800CM = 91.95

8.7CM
2
Cb = 1.75 + 1.05 ( 19.06 + 0.3 1 9.06 = 2.3
25.12 25.12

2.7 2.3

Cb = 2.3

717 X10° ( 2.3) 3590 X10° (2.3)
= 80.73= 180.65
2530 KG / CM2 2530 KG/ CM2

80.73 L / RT 180.65

POR LO TANTO SE UTILIZA
2
Fb 2 2530 ( 91.95 )
- 2530 = 1468.80
3 1080...

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