Calentamiento Global

Páginas: 2 (352 palabras) Publicado: 27 de febrero de 2013
1. Sobrecalentamiento
P1 = 18psi
T1= 10.5°F
P1 = 1.24 bar
T1 = -11.9°C
H1 = 242.34 KJKG
S1 = 0.96692 KJKS´K

| P = 1.0 bar | |
T | H | S |
-20 |236.54 | 0.9602 |
-11.9 | 243.1496 | 0.9857 |
-10 | 244.70 | 0.4918 |

| P = 1.4 bar | |
T | H | S |
-18.80 | 236.04 | 0.9322 |
-11.9 | 241.811 | 0.9544 |
-10 |243.40 | 0.9606 |

P | H | S |
1.0 | 243.1496 | 0.9857 |
1.24 | 242.34 | 0.96692 |
1.4 | 241.811 | 0.9544 |

2. Vapor Sobrecalentado
P2 = 162 psi = 11.16 barS2 = S1 = 0.96692 KJKG´K
P2 = 11.16 bar
T2 = 61.21 °C
H2 = 290.5 KJKG
S2 = 0.96692 KJKG´K

| P = 10 bar | |
T | H | S |
50 | 280.19 | 0.9428 |
57.09 |288.114 | 0.96692 |
60 | 291.36 | 0.9768 |

| P = 12 bar | |
T | H | S |
60 | 287.44 | 0.9527 |
64.2 | 292.243 | 0.96692 |
70 | 298.96 | 0.9868 |

P | H | T|
10 bar | 288.11 | 57.09 |
11.16 bar | 290.5 | 61.21 |
12 bar | 292.24 | 64.2 |

3. Liquido Saturado
P3 = 11.16 bar
T3 = 43.40 °C
H3 = 111.36 KJKG
S3 =0.4027 KJKG´K

| P3 = P2 = 11.16 bar | | |
P | T | S | H |
10 | 39.39 | 105.29 | 0.3838 |
11.16 | 43.40 | 111.36 | 0.4027 |
12 | 46.32 | 115.76 | 0.4164 |

4.Vapor Húmedo
P4 = P1 = 1.24 bar
H3 = H4 = 111.36 KJKG
T4 = -21.6° C
S4 = 0.4456

P | T | Hf | Hg | Sf | Sg | H | S |
1.2 | -22.36 | 21.32 | 233.86 | 0.0874 |0.9354 | 22.21 | 0.091 |
1.24 | -21.64 | 22.21 | 234.29 | 0.091 | 0.93476 | 111.36 | 0.4456 |
1.3 | -18.80 | 25.77 | 236..04 | 0.1055 | 0.9322 | 234.29 | 0.93476 |PROCESOS
1. WcM= h2 – h1 = 48.16 KJKG

2. QsM = h2 – h3 = 179.14 KJKG

3. H3 = h4

4. QeM = h1 – h4 = 130.98 KJKG

β = Qe/MWc/M = 130.9848.16 = 2.72
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