Elemeto finito

Páginas: 2 (439 palabras) Publicado: 23 de junio de 2010
Análisis por FEM.
Datos:
A = 0.008107 m2
E(1,2,3,4,5,6,7,8,9) = 207 mN.
E(10,11,12,13,14,15) = 73.1 mN.

Condiciones de frontera.
F1A, FIY = 2 kN.FBY, FDY, FEY, FFY, FHY = 2 kN.
UAX, UAY, UIY = 0.
KG = [18X18]
Tabla.
Elemento | Angulo | Cos(α) | Sen(α) | Cos(α)2 | Sen(α)2 | Seno(α)*cos(α) |
1 | 24 | 0.91355 |0.40674 | 0.83457 | 0.16543 | 0.37157 |
2 | 24 | 0.91355 | 0.40674 | 0.83457 | 0.16543 | 0.37157 |
3 | 24 | 0.91355 | 0.40674 | 0.83457 | 0.16543 | 0.37157 |
4 | 156 | -0.91355 | 0.40674 |0.83457 | 0.16543 | -0.37157 |
5 | 156 | -0.91355 | 0.40674 | 0.83457 | 0.16543 | -0.37157 |
6 | 156 | -0.91355 | 0.40674 | 0.83457 | 0.16543 | -0.37157 |
7 | 0 | 1.00000 | 0.00000 |1.00000 | 0.00000 | 0.00000 |
8 | 0 | 1.00000 | 0.00000 | 1.00000 | 0.00000 | 0.00000 |
9 | 0 | 1.00000 | 0.00000 | 1.00000 | 0.00000 | 0.00000 |
10 | 156 | -0.91355 | 0.40674 | 0.83457 |0.16543 | -0.37157 |
11 | 90 | 0.00000 | 1.00000 | 0.00000 | 1.00000 | 0.00000 |
12 | 53.13 | 0.60000 | 0.80000 | 0.36000 | 0.64000 | 0.48000 |
13 | 126.87 | -0.60000 | 0.80000 | 0. 36000 |0. 64000 | -0. 48000 |
14 | 90 | 0.00000 | 1.00000 | 0.00000 | 1.00000 | 0.00000 |
15 | 24 | 0.91355 | 0.40674 | 0.83457 | 0.16543 | 0.37157 |kG=AELC2CSCSS2-C2-CS-CS-S2-C2-CS-CS-S2C2CSCSS2
K1-3G=AEL0.834570.371570.371570.16543-0.83457-0.37157-0.37157-0.16543-0.83457-0.37157-0.37157-0.165430.834570.371570.371570.16543K4-6G=AEL0.83457-0.37157-0.371570.16543-0.834570.371570.37157-0.16543-0.834570.371570.37157-0.165430.83457-0.37157-0.371570.16543
K7-9G=AEL1 00 0-10 00-1000 1 0 0 0K10G=AEL0.83457-0.37157-0.371570.16543-0.834570.371570.37157-0.16543-0.834570.371570.37157-0.165430.83457-0.37157-0.371570.16543
K11,14G=AEL000 1 000-1 0-0 0-10001
K12G=AEL0.360.480.480.64-0.36-0.48-0.48-0.64-0.36-0.48-0.48-0.640.360.480.480.64...
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