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Páginas: 3 (516 palabras) Publicado: 30 de septiembre de 2010
EJERCICIO # 1

r = 15 ohmios

Fmm=I x N(numero de vueltas)

Fmm=I x N(numero de vueltas)

I= vr=4.5 v15 ohmios=0.3 A
Fmm=Φ .Rt
R=lµ1 . S(area)
µ1=µr x 4πx10-7
µ1=470x 4πx10-7=5.9x10-4
R1=lµ1 . S1
S1=60 x 45=2700mm2 =2.7x10-3 m2
R1=0.13m5.9 x10-4. (2.7x10-3 m2)
R1=81.6 K Rel. , óR1=81607.03 A.vwb
R2=lµ1 . S2
S2=50 x 45=2250mm2 =2.25x10-3 m2
R2=0.15m5.9 x10-4. (2.25x10-3 m2)
R2=112.9K Rel.
R3=lµ1 . S3
S3=S1=60 x 45=2250mm2 =2.25x10-3 m2
R3=1.7 x 10-3 m4πx10-7 .(2.25x10-3 m2)
R3=601.3 K Rel.
Rt=2R1+2R2+R3
Rt=2(81.6 K Rel)+2(112.9K Rel)+601.3 K Rel.
Rt=601.6 K Rel.
Φ=B .S1
Φ=0.88wbm2 x (2.25x10-3 m2)
Φ=1.98 x 10-3 wb
Fmm=Φ .Rt
Fmm=1.98 x10-3 wb x (601.6 K Rel.)
Fmm=1191.17 A.v
Fmm=I x N(numero de vueltas)
N= FmmI
N= 1191.17 A.v 0.3A
N=3970 vueltas

EJERCICIO # 2

N = 3500 vueltas
r = 450 ohmios
Calcular µr ?

I= vr=120 v450 ohmios=0.27A

Fmm=I x N(numero de vueltas)
Fmm=0.27 A x (3500 vueltas)
Fmm=933.33 A .v

Φ=B .S1
S1=25 x 35=875 mm2 =8.75 x 10-4m2

Φ=0.95wbm2 x (8.75 x 10-4m2)
Φ=8.31 x 10-4 wbFmm=Φ .R1
R1= FmmΦ =933.33 A .v8.31 x 10-4 wb=
R1=1122803 Rel.
R=lµ1 . S(area)
µ1=µr x µ0
R= lµr x µ0 x S1
µr= l R1 xµ0 x S1
µr= 0.08 m 1122803 Rel.x4πx10-7 x (0.875 m2)
µr=648R2=lµ1 . S2
µ1=µr x µ0
µ1=648 x (4πx10-7 )
µ1=8.14 x 10-4
S2=30 x 35=1050mm2 =1.05x10-3 m2
R3=lµ1 . S3
R2=0.065m8.14 x 10-4. (1.05x10-3 m2)
R2=76.02 K Rel.
R3=lµ1 . S3
S3=S1=25x 35=875 mm2 =8.75 x 10-4m2
R3=5x 10-4 m4πx10-7 . (8.75 x 10-4m2)
R3=454.7 K Rel.
Ra=R1+2R2=1122.8 KRel x 276.02 K Rel. =1198.82 KRel
Rb=R1+R3=1122.8 KRel x(454.7 K Rel.)=283.457KRel
Rc=Ra x RbRa+ Rb=283.457 KRel x (283.457 KRel)283.457 KRel + (283.457 KRel)=1577.5 KRel
Rt=R1+2R2+Rc
Rt=(1122.8 KRel)+2(76.02 K Rel.)+1577.5 KRel
Rt=2852.34 K Rel.
Φ=FmmR=933.33...

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