Jacg

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In= | 3Hp(746) | = | 7,849 A | | | |
| (√3)(220)0,85)(0,9) | | | | | |
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In= | 1Hp(746) | = | 2,559 A | | | |
| (√3)(220)0,85)(0,9) | | | | | |
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In= | 5Hp(746) | = | 12,759 A | | | |
| (√3)(220)0,85)(0,9) | | | | | |
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In= | 2Hp(746) |= | 5,118 A | | | |
| (√3)(220)0,85)(0,9) | | | | | |
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In= | 6Hp(746) | = | 15,355 A | | | |
| (√3)(220)0,85)(0,9) | | | | | |
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ft=1,00 por tabla 5,9 38 grados temp. Anb. -60 grados centigrados | | | |
fa=1,00 por tabla 5,7 tubo conduit 1-3 (3 diametros) | | | ||
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Ic= | 7,849 A | = | 7,849 A | | | | |
| 1(1) | | | | | | |
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Ic= | 2,559 A | = | 2,559 A | | | | |
| 1(1) | | | | | | |
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Ic= | 12,795 A | = | 12,795 A | | | | |
| 1(1) | | | | | | |
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Ic= | 5,118 A | = | 5,118 A | | | | |
| 1(1) | | | | || |
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Ic= | 15,355 A | = | 15,355 A | | | | |
| 1(1) | | | | | | |
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I cal=(7,849 A)(1,25)=9,811 A | | | | | |
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I cal=(2,559 A)(1,25)=3,198 A | | | | | |
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I cal=(12,795 A)(1,25)=15,993 A | | | | | |
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I cal=(5,118A)(1,25)=6,397 A | | | | | |
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I cal=(15,355 A)(1,25)=19,193 A | | | | | |
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CALIBRE | | | | | | | |
VINANEL 2000 | RESISTENCIA(Ω) | | | | | |
M1=18 | | 14=8,45 | | | | | |
M2=18 | | 14=8,45 | | | | | |
M3=20 | | 14=8,45 | | | | | |
M4=14 | | 14=8,45 | | | | | |M5=20 | | 14=8,45 | | | | | |
M6=20 | | 14=8,45 | | | | | |
M7=18 | | 14=8,45 | | | | | |
M8=20 | | 14=8,45 | | | | | |
M9=20 | | 14=8,45 | | | | | |
M10=14 | | 14=8,45 | | | | | |
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%e1= | (√3)(8,45x10^-3)(100)(8,2 m)(7,849 A) | = | 0,428 | | | |
| 220 v | | | | | |
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%e2= | (√3)(8,45x10^-3)(100)(4,7 m)(7,849 A) | = | 0,245 | | | |
| 220 v | | | | | |
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%e3= | (√3)(8,45x10^-3)(100)(6,2 m)(2,559 A) | = | 0,105 | | | |
| 220 v | | | | | |
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%e4= | (√3)(8,45x10^-3)(100)(6m)(12,795 A) | = | 0,510 | | | |
| 220 v | | | | | |
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%e5= |(√3)(8,45x10^-3)(100)(7m)(2,559 A) | = | 0,119 | | | |
| 220 v | | | | | |
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%e6= | (√3)(8,45x10^-3)(100)(8 m)(2,559 A) | = | 0,136 | | | |
| 220 v | | | | | |
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%e7= | (√3)(8,45x10^-3)(100)(14,5m)(7,849 A) | = | 0,757 | | | |
| 220 v | | | | | |
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%e8= | (√3)(8,45x10^-3)(100)(17,5)(5,118 A) | = | 0,595 | || |
| 220 v | | | | | |
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%e9= | (√3)(8,45x10^-3)(100)(22m)(5,118 A) | = | 0,749 | | | |
| 220 v | | | | | |
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%e10= | (√3)(8,45x10^-3)(100)(23,5m)(15,355 A) | = | 2,400 | | | |
| 220 v | | | | | |
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tablas de capacidad de conduccion de corriente area | | | ||
tabla 5.1 diametro exterior nominal | | | | | |
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H1 = 3,5mm2 | | | | | | |
H10=3,5 mm2 | | | | | | |
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A= | π(3,5 mm2)^2 | = | 9,6211 mm2 | | | |
| 4 | | | | | |
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diametros y areas interiores……tabla No 4 pareo gruesa 40% | | | | |
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