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  • Publicado : 1 de marzo de 2012
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1. 2A + 3B

 2A = 2x

210 213 432 3 -1 0 2 1 4 2 2 2

=

420 426 864 9 -3 0 6 3 12 6 6 6



3B = 3x Luego

=

 2A+3B=

4 2 0 4 2 6 8 6 4

+

9 -3 0 6 3 12 6 6 6

=

13 -2 0 10 0 -1 14 12 10

2. (A – B)(5B +A ) 210 213 432 3 -1 0 2 1 4 2 2 2 -1 2 0 0 0 -1 2 1 0

 A–B=

-

=

Acuña Ventosilla, Brayan Acedo Ceña, Marvil Honores Vaca, Carlos

 5B = 5x

3-1 0 2 1 4 2 2 2

15 -5 0 = 10 5 20 10 10 10 210 213 432 17 -4 0 12 6 23 14 13 12

 5B + A=

15 -5 0 10 5 20 10 10 10

+

=

→ (A – B)(5B +A ) =

1 2 0 0 0 -1 2 1 0

.

17 -4 0 12 6 23 14 13 12

→ (A – B)(5B +A ) =

-1+24+0 0+ 0-10 34+12+0 7 16 46 -14 -13 -12 46 -2 23

4+12+0 0 + 0 -13 -8+6+0

0+46+0 0+0-12 0+23+0

→ (A – B)(5B +A ) =

3. A.C+B.C 210 213 432 3 -1 0 21 4 2 2 2 -2 3 2 -4 6 -7 -2 3 2 -4 5 -7 -2 2 13 -19 3 -14 -6-2+0 -4+2+20 -4+4+10 9+4+0 6-9-28 6-8-14

 A.C =

.

=

 B.C=

.

=

Acuña Ventosilla, Brayan Acedo Ceña, Marvil Honores Vaca, Carlos



-8 13 18 -26 10 -16

→ A.C+B.C =

-2 2 13 -19 3 -14

+

-8 13 18 -26 10 -16

=

-10 15 31 -45 18 -30

1. X-B2=A.B X=A.B+B2  A.B = 210 213 432 . 3 -1 0 2 1 4 2 2 2 =8 -1 4 14 5 10 22 3 16 7 -4 -4 16 7 12 14 4 12

 B2 =BxB =

3 -1 0 2 1 4 2 2 2

.

3 -1 0 2 1 4 2 2 2

=

X=A.B+B =

2

8 -1 4 14 5 10 22 3 16

+

7 -4 -4 16 7 12 14 4 12

=

15 -5 0 30 12 22 36 7 28

Acuña Ventosilla, Brayan Acedo Ceña, Marvil Honores Vaca, Carlos

2. f(A)=2A2 – 4A -5 210 213 432 210 213 432 4+2+0 4+2+12 8+6+8 2+1+0 2+1+9 4+3+6 0+3+0 0+3+6 0+9+4

A=AxA=

2

.

=

=

6 3 3 18 12 9 20 12 13 6 3 3 18 12 9 20 12 13 12 6 6 36 24 18 40 26 26

→2A = 2x

2

=

→4A= 4x

210 213 432 100 010 001

=

8 4 0 8 4 12 16 12 8 500 050 005

→-5= 5x

=

f(A)=2A2 – 4A -5
12 6 6 36 24 18 40 26 26 8 4 0 8 4 12 16 12 8 500 050 005 9 2 6 28 25 6 24 14 23

=

-

+

=

Acuña Ventosilla, Brayan Acedo Ceña, Marvil Honores Vaca,Carlos

3. (A+B)t = At+ Bt 210 213 432 3 -1 0 2 1 4 2 2 2 500 427 654

A+B =

+

=

→(A+B) =

t

546 025 074 210 213 432

 A=

→ A =

t

224 113 032

 B=

3 -1 0 2 1 4 2 2 2

→ B =

t

3 2 2 -1 1 2 0 4 2 546 025 074

 At+ Bt =

224 113 032

+

3 2 2 -1 1 2 0 4 2

=

→(A+B)t = At+ Bt 546 025 074 546 025 074

=

Acuña Ventosilla, Brayan AcedoCeña, Marvil Honores Vaca, Carlos

1. |A|+|B| 25 38 -3 -3 -5 4

A=



|A|= (

25 38 -3 -3 -5 4

=16 – 15 = 1

B=



|B|=

= -12 -15 = -27

→|A|+|B|= 1 +(-27)= -26/ 2. |C| -2 3 9 5 -4 4 3 3 -3 -2 3 9 5 -4 4 3 3 -3

C=

→ |C| =

= (-20+36+135)-(-108+ (-45)+ (-24))=120-(-177)=297/

Acuña Ventosilla, Brayan Acedo Ceña, Marvil Honores Vaca, Carlos

3. |D|

D=

2 6 -51

-3 -3 6 -4

0 2 0 3

-4 1 3 2 -3 2 1 6 0 3 -4 3 2 -3 0 -4 6 0 3 -4 3 2

|D|

=(-1)1+1. (1)

+(-1)2+1. (-6)

+(-1) . (-5)

3+1

-3 0 -4 -3 2 1 -4 3 2

+(-1) . (-5)

3+1

-3 0 -4 -3 2 1 6 0 3

|D|=2{((-3)(0)(2)+(2)(3)(-4)+(6)(3)(1))-((1)(0)(4)+(2)(6)(2)+(3)(3)(-3))} =6{((-3)(0)(2)+(0)(3)(-4)+(6)(3)(4))-((-4)(0)(-4)+(0)(6)(2)+(3)(3)(-3))}=5{((-3)(2)(2)+(0)(1)(-4)+(-3)(3)(-4))-((-4)(2)(-4)+(0)(-3)(2)+(1)(3)(-3))} =1{((3)(2)(3)+(0)(1)(6)+(-3)(0)(-4))-((-4)(2)(6)+(0)(-3)(3)+(1)(0)(3))} |D|=2{(0-24+18)-(0+24-27)}-6{(0+0-72)-(0+0-27)}-5{(-12+0+36)(32+0-9)}-1{(18+0+0)-(-48+0+0)} |D|=2(-3)-6(45)-5(1)-66)= -6 + 270 - 5 - 66 = 193/

Acuña Ventosilla, Brayan Acedo Ceña, Marvil Honores Vaca, Carlos

1. Adj |A| 1 1 3 2 -1 4 0 -1 1

A=

-1 4 -1 1 Adj(A)=

-

1 3-1 1 13 01

13 -1 4

- 01
2 -1 0 -1

2 4

-

13 24 1 1 2 -1

-

1 1 0 -1

(-1+4) -(1+3) Adj(A)= -(2-0) (-2-0) (1-0) -(-1-0)

(4+3) -(4-6) (-1-2) =

3 -4 -2 -2 1 1

7 2 -3

Acuña Ventosilla, Brayan Acedo Ceña, Marvil Honores Vaca, Carlos

2. Adj |B| 5002 1102 0021 1001 102 021 001 Adj(B)= 102 021 101 112 001 101 110 002 100 002 021 001 502 021 101 502 001 101 500 002...
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