Negocios

EVALUACIÓN FINAL DE ESTADÍSTICA GENERAL
Nombre y apellido: Sandra Rosmery Reyna Anampa
1.-
A).-
V | N | = | N! | = | 48! | = | 1,241 |
|K | | (N-K)! | | (48-4)! | | 2,658 |
| | | | | | | |
B).-
P | | = | N! |
| N | | |

P | | = | 15! |
| N | | |P | | = | 1,308 |
| N | | |

2.-
A).-
P | | = | 12! |
| N | | |

P | | = | 479,00 |
| N | | |
B).-
Pcn | | = |(12-1)! |
| | | |
Pcn | | = | 39,916 |
| | | |

3.-
A).- {csc,scs,ccs,scc,ssc,css,sss,ccc}
B).-
A= “scs,ssc,css”3/8 = 0.375 = 37.5%
B= “csc,ccs,scc” 3/8 = 0.375 = 37.5%
C= “csc,scs,ccs,scc,ssc,css,ccc”7/8 = 0.875 = 87.5%
D= “csc,ccs,scc,ccc” 4/8 = 0.5 = 50%
C).-
P(A) B) = P(A) x P(B) = 0.375x 0.375 = 0.140625 = 14%
P(CC) = 1- P(c) = 1- 0.875 = 0.125 = 13%
P(DC) = 1- P(D) = 1- 0.5 = 0.5 = 50%
(Cc D d) = P(C) x P(D) = 0.125 x0.5 = 0.0625 = 6%

4.- Datos:
P(A U B) = 0.8; P (AC) = 0.45; P(A B) = 0.15

B 0.2

B 0.2

A 0.45
A 0.45

0.15
0.15

P(A UB) = 0.8 = 80%
P(A U B) = 0.8 = 80%

P(A) = 0.55 = 55%
P(B) = 0.25 = 25%
- Calcular las probabilidades:
A).-
P(A) = 0.55 = 55%
P( (AUB)C) = 1 – P(AUB) = 1- 0.8 = 0.2 = 20%
P(AC B) = 0.45 * 0.25 = 0.1125 = 11%
B).-
P(A/B)
=
=
= 0.6
= 60%
P(B/A)
=
=
=27%