Obtención del benzhidrol

Solo disponible en BuenasTareas
  • Páginas : 6 (1285 palabras )
  • Descarga(s) : 0
  • Publicado : 10 de septiembre de 2012
Leer documento completo
Vista previa del texto
CALCULOS DE LA PRÁCTICA
Datos de la práctica
Solución | X1 | V1 metano | V2 agua | X2 |
1 | 0 | 0 | 50 | 1 |
2 | .1 | 10 | 40 | 0.9 |
3 | .2 | 18 | 32 | 0.8 |
4 | .3 | 24.6 | 25.4 | 0.7 |
5 | .4 | 30 | 20 | 0.6 |
6 | .5 | 34.6 | 15.4 | 0.5 |
7 | .6 | 38.6 | 11.4 | 0.4 |
8 | .7 | 42 | 8 | 0.3 |
9 | .8 | 45 | 5 | 0.2 |
10 | .9 | 47.6 | 2.4 | 0.1 |
11 | 1.0 | 50 | 0 | 0 |V1 = x1PM1ρ1X1PM1ρ1+x2PM2ρ2 =
V1=0*32.0316 gr/grmol0.791 gr/ml0*32.0316gr/grmol0.791gr/ml+1*18.016gr/grmol0.997gr/ml = 0ml
V2=0.1*32.0316 gr/grmol0.791 gr/ml0.1*32.0316gr/grmol0.791gr/ml+0.9*18.016gr/grmol0.997gr/ml =0.19936 ml
V3=0.2*32.0316 gr/grmol0.791 gr/ml0.2*32.0316gr/grmol0.791gr/ml+0.8*18.016gr/grmol0.997gr/ml = 0.35908 ml
V4= 0.3*32.0316 gr/grmol0.791gr/ml0.3*32.0316gr/grmol0.791gr/ml+0.7*18.016gr/grmol0.997gr/ml = 0.48991 ml
V5=0.4*32.0316 gr/grmol0.791 gr/ml0.4*32.0316gr/grmol0.791gr/ml+0.6*18.016gr/grmol0.997gr/ml =0.59904 ml
V6=0.5*32.0316 gr/grmol0.791 gr/ml0.5*32.0316gr/grmol0.791gr/ml+0.5*18.016gr/grmol0.997gr/ml =0.69145 ml
V7=0.6*32.0316 gr/grmol0.791 gr/ml0.6*32.0316gr/grmol0.791gr/ml+0.4*18.016gr/grmol0.997gr/ml =0.77072 ml
V8=0.7*32.0316 gr/grmol0.791gr/ml0.7*32.0316gr/grmol0.791gr/ml+0.3*18.016gr/grmol0.997gr/ml =0.83946 ml
V9=0.8*32.0316 gr/grmol0.791 gr/ml0.8*32.0316gr/grmol0.791gr/ml+0.2*18.016gr/grmol0.997gr/ml = 0.89964 ml
V10=0.9*32.0316 gr/grmol0.791 gr/ml0.9*32.0316gr/grmol0.791gr/ml+0.1*18.016gr/grmol0.997gr/ml = 0.95276 ml
V11=1*32.0316 gr/grmol0.791 gr/ml1*32.0316gr/grmol0.791gr/ml+0.0*18.016gr/grmol0.997gr/ml = 1 ml
Empuje dela solución
Emsol= w aire – w sol (1-11)
E1=5.99 gr-3.32 gr = 2.67 gr
E2=5.99 gr-3.39 gr = 2.60 gr
E3=5.99 gr-3.44 gr = 2.55 gr
E4=5.99 gr-3.51 gr = 2.48 gr
E5=5.99 gr-3.57 gr = 2.42 gr
E6=5.99 gr-3.61 gr = 2.38 gr
E6=5.99 gr-3.70 gr = 2.29 gr
E8=5.99 gr-3.73 gr = 2.26 gr
E9=5.99 gr-3.79 gr = 2.21 gr
E10=5.99 gr-3.83 gr = 2.16 gr
E11=5.99 gr-3.83 gr = 2.12 gr
Volumen del BuzoVBUZO=EsolucionρH2O
VBUZO=2.67 gr0.997 gr/ml
VBUZO=2.67803 ml
Densidad de las Soluciones
ρSOLUCION=EsolucionVbuzo
ρ1=2.67gr2.67803 ml = 0.997 gr/ml
ρ2=2.60gr2.67803 ml = 0.97086 gr/ml
ρ3=2.55gr2.67803 ml = 0.95219 gr/ml
ρ4=2.48gr2.67803 ml = 0.92605 gr/ml
ρ5=2.42gr2.67803 ml = 0.90365 gr/ml
ρ6=2.38gr2.67803 ml = 0.88871 gr/ml
ρ7=2.29 gr2.67803 ml = 0.8555 gr/ml

ρ8=2.26 gr2.67803 ml =0.8439 gr/ml
ρ9=2.2 gr2.67803 ml = 0.8214 gr/ml
ρ10=2.16 gr2.67803 ml = 0.8065 gr/ml
ρ11=2.12 gr2.67803 ml = 0.7916 gr/ml
Volúmenes Específicos

Ve=1ρsol
Ve=10.997 gr/ml = 1.003 ml
Ve=10.97086 gr/ml = 1.030 ml
Ve=10.95219 gr/ml = 1.05021 ml
Ve=10.92605 gr/ml = 1.07986 ml
Ve=10.90365 gr/ml = 1.10662 ml
Ve=10.88871 gr/ml = 1.1252 ml
Ve=10.8555 gr/ml = 1.1689 ml
Ve=10.8439 gr/ml = 1.1849 mlVe=10.8214 gr/ml =1.2174 ml
Ve=10.8065 gr/ml =1.2399 ml
Ve=10.7916 gr/ml =1.2632 ml

Peso Molecular Promedio
PMPROMEDIO=X1 PM1+X2PM2
PMPROMEDIO 1 =(0)(32.0316 gr/gr mol)+(1)(18.016 gr/gr mol) =18.016
PMPROMEDIO 2 =(0.1)(32.0316 gr/gr mol)+(0.9)(18.016 gr/gr mol) =19.4175
PMPROMEDIO 3 =(0.2)(32.0316 gr/gr mol)+(0.8)(18.016 gr/gr mol) =20.8191
PMPROMEDIO 4 =(0.3)(32.0316 gr/grmol)+(0.7)(18.016 gr/gr mol) =22.2206
PMPROMEDIO 5 =(0.4)(32.0316 gr/gr mol)+(0.6)(18.016 gr/gr mol) =23.6222
PMPROMEDIO 6 =(0.5)(32.0316 gr/gr mol)+(0.5)(18.016 gr/gr mol) =25.0238
PMPROMEDIO 7 =(0.6)(32.0316 gr/gr mol)+(0.4)(18.016 gr/gr mol) =26.4253
PMPROMEDIO 8 =(0.7)(32.0316 gr/gr mol)+(0.3)(18.016 gr/gr mol) =27.8269
PMPROMEDIO 9 =(0.8)(32.0316 gr/gr mol)+(0.2)(18.016 gr/gr mol) =29.2284PMPROMEDIO 10 =(0.9)(32.0316 gr/gr mol)+(0.1)(18.016 gr/gr mol) =30.63
PMPROMEDIO 11=(1)(32.0316 gr/gr mol)+(0)(18.016 gr/gr mol) =32.0316
Volumen
V=Ve *PMPROM
V1=1.003 ml*18.016 = 18.07005 ml
V2=1.030 ml*19.4175 = 20.0000 ml
V3=1.05021 ml*20.8191 = 21.86443 ml
V4=1.07986 ml*22.2206 = 23.99514 ml
V5=1.10662 ml*23.6222 = 26.14080 ml
V6=1.1252 ml*25.0238 = 28.15678 ml
V7=1.1689 ml*26.4253 =...
tracking img