Quimica Aplicada

PRIMERA PARTE

P (dinas/cm2) | V (cm3) | PV (erg) |
782,752.01 | 9 | 7,044,768.09 |
846,390.36 | 8.3 | 6,915,122.88 |
937,280.4 | 8 |6,560,962.8 |
1,015,902.1 | 7.1 | 9,095,412.6 |

SEGUNDA PARTE

T (°C) | T (°K) | V (cm3) | V/T (cm3/°K) |
22 |295 | 9.3 |0.031 |
40 | 313| 10.1 | 0.03226 |
60 | 333 | 11.6 | 0.03483 |
80 | 353 | 12.5 | 0.03541 |

TERCERA PARTE
T (°C) | T (°K) | V (cm3) | P (dinas/cm2) | PV/T(erg(°K) |
40 | 313 | 9.7 | 864,390.36 | 26,235.49 |
60 | 333 | 11 | 937,280.4 | 28,146.55 |

 CALCULOS PRESIONES

P0 = PDF + PÉmboloPÉmbolo =   F =   mg / π (r^2)
PÉmbolo = 8gr(981cms2) / π (0.91cm)2
PÉmbolo = 3008.61 dinascm2

PDF = 585 mmHg.
760 mmHg ---------- 1.013x 106   dinascm2
585 mmHg ----------       X

X=779743.4 dinascm2
P0 = 3008.61 dinascm2   + 779743.4 dinascm2
P0 = 782,752.01 dinascm2
P1 = P0 + PPESA 1
PPesa 1 = me+mpesa 1g / A e
PPesa 1 = 8gr+211.4gr(981cms2) / π(0.91cm)2
PPesa 1 =218.4.5 gr(981cms2) / π(0.91cm)2
PPesa 1 = 82354.8127 dinascm2
P1 = P0 + PPESA 1
P1 = 782752.01 dinascm2+ 82354.8127 dinascm2
P1 = 865,106.8228 dinascm2

P2 = P0 + PPESA 2
PPesa 2 = me+mpesa2g/ Ae
PPesa 2 = 8gr+401.4 gr(981cms2)π(0.91cm)2
PPesa 2 = 409.4 gr(981cms2)π(0.91cm)2
PPesa 2 = 154377.56 dinascm2
P2 = P0 + PPESA 2
P2 = 782752.01 dinascm2 + 154377.56 dinascm2
P2 = 937,129.57dinascm2

P3 = P0 + PPESA 1 Y 2
PPesa 1 y 2 = me+mpesa1+mpesa2gAe
PPesa 1 y 2 = (8gr+211.4.5gr+401.4 gr(981cm/s2)) / (π(0.91cm)2)
PPesa 1 y 2 = 620.8 gr(981cm/s2) / π(0.91cm)2
PPesa 1 y 2=234092.8011 dinas/cm2
P3 = P0 + PPESA 1 Y 2
P3 = 782752.01 dinas/cm2 + 234092.8011 dinas/cm2
P3 = 1,016,844.811 dinascm2

2.- Con los datos obtenidos de la primera y segunda parte, construya las...