Tegnologo

R1=150Ω R2=130Ω Rt= R1+R2 Rt= 150Ω+130Ω = 280Ω
It= V/r 6v/280Ω = 0.021 A
v= 6vPT=v*I 6v*0.021A = 0.126w
V = It*Rt 0.021A * 280Ω =5.88V
V1= I*R1 0.021A*150Ω = 3.15 v
V2=I* R2 0.021A*130Ω =2.73 v
PR1= V1*I 3.15V*0.021A= 0.066W
PR2=V2*I 2.73V*0.021A=0.057W
PT=0.066+0.057=0.123WRT=R1*R2/RI+R2 RT=12KΩ*150KΩ/12KΩ+150KΩ=300KΩR1=12KΩ R2= 150KΩ IT=v/r 0.02A
PT=V*I 6V*0.02=0.12W
U=6vI1=V/R1 6/12=0.5MA
I2=V/R2 6/150=0.04MA
PR1= v*I1 6V*0.5MA=3W
PR2=V*I2 6V*0.04=0.24W

R2=150KΩRA=R2+R3=150+680=830KΩ+R1=830KΩ
R1=150KΩ RT=RA+150=830KΩ +150KΩ=980KΩ
R3=680KΩIT=V/RT= 6V/980KΩ= 0.006A
P=V*I 6V*0.006A=0.036W6v
I1=V/R1 6V/150KΩ=0.04A
I2=V/R2 6V/150KΩ=0.04A
I3=V/R3 6V/680KΩ=0.008ACONCLUCIONES
CIRCUITO SERIE
-hemos concluido que es de gran importancia saber cuanta corriente se puede aplicar al circuito teóricamente mediante la ley de Ohm, ya que así no se quemarán las...