Tipos de presas

NOMBRE___________________________________________________ ID_________

CALCULAR EL FACTOR DE SEGURIDAD POR VOLTEO , CONSIDERANDO LA FUERZA POR SUBPRESIÓN, ESFUERZOS EXCESIVOS

EJEMPLO:

FHW =[pic]

yk = 40 m

FSUB = [pic]

W1 = (2.4 ton/m3)(10*125) = 3000 ton
W2 = (2.4 ton/m3)(71.25*109.615*0.5) = 9372.05 ton

MOMENTO VOLTEO:
Mm = 7200(40)+1950(54.166) = 393625 ton-mMOMENTO RESISTENTE:
MR = 3000(76.25)+9372.08(47.50) = 673923.8 ton-m

F.S. = [pic]

FH = [pic]
yk = [pic]

W1 = (conc Vol1 = 2400 kg/m3 (10*125*1) =3’000,000 kg

W2 = (conc Vol2 = 2400 kg/m3 (75*[pic]*1) = 9’926,100 kg

Momento de Volteo:
(sin subpresión) Mm = 7200 ton * (40) = 288,000 ton-m

Momento Resistente:MR = 3000 ton (80) + 9926.1 ton [pic] = 736,305 ton -m
F.S. = [pic]= 2.55 > 1.5 ( OK
Momento de Volteo:
(con subpresión) Mm = 7200 ton*(40)+[pic]*(1)[pic]= 432,500ton-m

Momento Resistente: MR = 736,305 ton-m

F.S. = 1.7 > 1.5 ( OK

UBICACIÓN DE Ry EN LA BASE

(Mo = 0
Ry (x) – 3000 ton (5m) – 9926.1 ton (35m) + 2550 ton[pic] - 7200 (40) = 0
X = 55.721 m de “o”

CÁLCULO DE (min y (máx

Ec. 1

55.721 m = [pic]

55.721 m = [pic]

55.721 m = 0.34816 (MIN + 0.232104 (MAX – 0.232104 (MIN55.721 m = 0.116056 (MIN + 0.232104 (MAX

Ec. 2

SUSTITUYENDO Ec. 2 en Ec. 1

[pic] = 10376.1 ton

21.25 (MIN + 10202.98 = 10376.1

(MAX = 240.07 – 0.5 (MIN-----------------------
y

71.25 m

120 m

5 m

10 m

81.25 m

0.4 ( h

0.65

1

[pic]

[pic]

y = 109.615 m

y

x = 81.25

pie

(

120 m

5 m

10m

85 m60TON/M2

0.68

1

W1

W2

y=14.71

110. 29

120 m

(min

Subpresión
60TON/M2

(max

5 m

10m

(

W1

W2

Ry

X

85 m

FH

o

CALCULO DE LA SUBPRESIÓN...