Algebra

Páginas: 24 (5829 palabras) Publicado: 9 de enero de 2013
1.- >> quika=[3 6;-2 3]
quika =

3 6
-2 3
>> Belen=[9;4]
Belen =

9
4
>> Carla=[quika Belen]
Carla =

3 6 9
-2 3 4
>> Carla(1,:)=Carla(1,:)/3
Carla =

1 2 3-2 3 4
>> Carla(2,:)=Carla(2,:)+2*Carla(1,:)
Carla =

1 2 3
0 7 10
>> Carla(2,:)=Carla(2,:)/7
Carla =

1 2 3
0 1 10/7
>> Carla(1,:)=Carla(1,:)-2*Carla(2,:)
Carla =1 0 1/7
0 1 10/7
>> rref(Carla)
ans =

1 0 1/7
0 1 10/7
2.- ka=[3 6;2 4]
ka =

3 6
2 4
>> Be=[9;6]
Be =

9
6
>> Ca=[ka Be]
Ca =

36 9
2 4 6
>> rref(Ca)
ans =

1 2 3
0 0 0
No tiene solución
3.- ka=[4 6 ;6 9]
ka =

4 6
6 9
>> Be=[5;15]
Be =

5
15

>> Col=[kaBe]
Col =

4 6 5
6 9 15
>> rref(Col)
ans =

1 3/2 0
0 0 1
4.- >> ola=[3 -6;-2 4]
ola =

3 -6
-2 4
>> la=[9;6]
la =

9
6>> m=[ola la]
m =

3 -6 9
-2 4 6
>> rref(m)
ans =

1 -2 0
0 0 1
5.- >> yu=[1 1 1;-2 -1 2;-3 2 3]
yu =

1 1 1
2 -1 2
-32 3
>> u=[2;4;3]
u =

2
4
3
>> l=[yu u]
l =

1 1 1 2
-2 -1 2 4
-3 2 3 3
>> rref(l)
ans =

1 0 0 9/140 1 0 -6/7
0 0 1 31/14
6- >> CO=[1 -2 1;2 3 -2;-1 -4 3;]
CO =

1 -2 1
2 3 -2
-1 -4 3 >> CA=[1;5;4]
CA =

1
5
4>> COCA=[CO CA]
COCA =

1 -2 1 1
2 3 -2 5
-1 -4 3 4
>> COCA(2,:)=COCA(2,:)-2*COCA(1,:)
COCA =

1 -2 1 1
0 7 -4 3-1 -4 3 4

>> COCA(3,:)=COCA(3,:)+1*COCA(1,:)
COCA =

1 -2 1 1
0 7 -4 3
0 -6 4 5
>> COCA(2,:)=COCA(2,:)/7
COCA =

1 -2 1 1...
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