Darwin

Laboratorio#1 “Las Fuerzas”

Presentado Por:
Laura Chávez
Fabio Muñoz
Felipe Olarte
Jhonattan Peña

Profesor:
Mario Calderón

16 de Agosto de 2012Colegio Distrital Paulo Freire

Laboratorio#1 Las Fuerzas
Cateto Opuesto “Papel Contad” = 10cm-12cm-14cm.
Cateto Opuesto “Tela” = 17cm-14.5cm-12.5cm.
Catato Opuesto“Cartón Paja” = 11cm-10cm-11.5cm.


24.2

24.2





Cartón Paja Con Tela
Co = h * seno Φ = co/h = seno Φ = 14.6/35= 0.41
Φseno-1(0.41) Φ= 24.2°Cartón Paja Con Contad
Co = h * seno Φ = co/h = seno Φ = 12/35= 0.34

Φseno-1(0.34) Φ= 19.8°

Cartón Paja
Co = h * seno Φ = co/h = seno Φ = 10.8/35 = 0.30Φseno-1(0.30) Φ= 17.4


Cartón Paja Con Tela
M1
Wx = w1 * seno24.2° = 0.07kg*9.8m/s * seno24.2° = 0.28 N
Wy = w1 * coseno24.2° =0.07kg*9.8m/s * coseno24.2° = 0.62 N

∑Fx = 0
Wx + Fr = 0
Fr = Wx
Fr = 0.28 N
∑Fy = 0
-Wy + N = 0
N = Wy
N= 0.62N
Fr=M*N Fr/N = M
M =0.28N/0.62N = 0.45

Cartón Paja Con Contad
M1
Wx = w1 * seno19.8° = 0.07kg*9.8m/s * seno19.8° = 0.23 N
Wy = w1 * coseno19.8° = 0.07kg*9.8m/s *coseno19.8° = 0.64 N

∑Fx = 0
Wx + Fr = 0
Fr = Wx
Fr = 0.23 N
∑Fy = 0
-Wy + N = 0
N = Wy
N= 0.64N
Fr=M*N Fr/N = M
M =0.23N/0.64N = 0.35

Cartón Paja Con Tela
M1
Wx = w1 * seno17.4° = 0.07kg*9.8m/s * seno17.4° = 0.20 N
Wy = w1 * coseno17.4° = 0.07kg*9.8m/s * coseno17.4°= 0.65 N

∑Fx = 0
Wx + Fr = 0
Fr = Wx
Fr = 0.20 N
∑Fy = 0
-Wy + N = 0
N = Wy
N= 0.65N
Fr=M*N Fr/N = M
M = 0.20N/0.65N = 0.30