Ecuaciones

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  • Publicado : 24 de mayo de 2011
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Resuelve las siguientes ecuaciones de primer grado con una incógnita
i. 2x – 34 =120
ii. 9x + 8 = 7x + 16
iii. 4x + 5 = 3x +12
iv. 7x + 9 = 57 + x
v. 5x– 13 = 2x – 4
vi. x + 17 = 3x + 1
vii. 6x + 160 = 40 + 8x
viii. 9 + 9x =117 – 3x
ix. 2x + 1 = 3x – 2
x. 25 – 2x = 3x –35
xi. 4x +17 = 3x + 24
xii. 7x – 3 =21x – 9
xiii. 1 + 8x =-64x + 46
xiv. 5x – 11 = 15x –33
xv. 15x – 60 = -12x –54
xvi. 2x + 17 = 3x +2
xvii. 60 – 5x = x –12
xviii. 70 – 3x = 14 + x
xix. 100 –3x = 5x –28
xx. 10x – 17 = 4x + 85
xxi. 3x + 1 = 7x – 11
xxii. 47 – 2x = 5 + 12x
xxiii. 10 – 9x = -7x + 21
xxiv. 11x – 100 = 2x – 1
xxv. 25 – 2x = 3x – 80xxvi. 100 – 5x = 4x – 71
xxvii. 19 + 8x =12x + 14
xxviii. 21y – 3 = 10y +195
xxix. 2 – 6x = 36x – 5
xxx. 4 – 24x + 500 = -3x
xxxi. x – 5(x – 2)=6x
xxxii. 3x + 7= 2(x + 8)
xxxiii. 5x = 8(5x – 3) – 4
xxxiv. 2(x – 6) = 3x – 19
xxxv. 5 + 5(x – 13) = x
xxxvi. x – 2 = -3(4 – 2x)
xxxvii. 2(9x – 49) = 15x + 10
xxxviii. 120 =2x – (15 – 7x)
xxxix. 60x + 1 = 3(3 + x)
xl. 15(x – 1) + 20(x + 1) = 75
xli. 4x + 7(2x – 1) = x + 163
xlii. 3 – 4x(25 – 2x) = 8x2 + x – 300
xliii. 14x + 3(8x–3) – 295=0
xliv. 5[2x – 4(25 – 2x)] = -10x + 20
xlv. 3x – 4(x – 2) = x – 10
xlvi. 5x – 3(x + 5) = 3x + 10
xlvii. 7(x – 18) = 3 (x – 14)
xlviii. 5 (x + 4) = 7x– 2
xlix. 38 + 7(x – 3) = 9(x + 1)
l. 3 (3+ 4x) = 4x + 15
li. 104 – 9x = 4(5x – 3)
lii. x + 3 = 11(2x – 15)
liii. 15x = 7(2 + 9x) – 30
liv. 5(3x + 2) = 8(9- 2x)
lv. x – 13 = 4[3x – 4(x - 2)]
lvi. 9(13 – x) – 4x = 5(21 – 2x) + 9x

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