Nociones de fisica

CENTRO DE ESTUDIOS DE BACHILLERATO 5/8

CÁTEDRA: FÍSICA

CATEDRÁTICO: ROBERTO LORENZO ELORZA MENDOZA

INTEGRANTES:
* CYNTHIA KARINA HERNÁNDEZ MARTÍNEZ
* VALERIA JOSÉ GARCÍA

GRUPO:331

Método analítico

F1 y = 150 sin 90° = 150 ton
F2 x = 80 cos 50° = -51.42 ton
F2 y = 80 sin 50° = - 61.28 ton
F3 x = 90 cos 60° = 45 ton
F3 y = 90 sin 60° = - 77.94 ton
∑ Fx = 0 – 51.42+ 45
= -6.42
∑Fy = 150 – 61.28 – 77.94
= 10.78
FR= ∑Fx2+∑Fy2=
FR= (6.42)2+(10.78)2 = 122.62
tg θ = ∑Fy ∑Fx θ = tg-1 ∑Fy ∑Fxθ=tg-1 (1.679127726)
= 10.786.42 = 1.679127726
FR= 122 ton
<) 59°

V1y = 20 cos 90° = 0 km/h
V2x = 80cos 180° = - 80 km/h
V3x = 300 cos 65° = - 126.78 km/h
V3y = 300 sin 65° = -271.89 km/h

∑Vx = - 80 – 126.78
= - 206.78
∑Vy = - 271.89
= - 271.89
VR= ∑Fx2+∑Fy2=
VR=(-206.78)2+(-271.89)2 = 206.12 km/h
tgθ= ∑Fy∑Fx θ= tg-1 ∑Fy∑Fx = -271.89-206.78 = 1.314875713
FR= 206.12 km/h
<) = 52°

a 1x =10 cos 60° = 5 m/s2
a1y= 10 sin 60° = 8.66 m/s2
a2x = 9 cos 20° = 8.45 m/s2
a2y = 9 sin 20° = 3.07 m/s2
a3x= 9 cos 45°= -6.36 m/s2
a3y= 9 sin 45°= - 6.36 m/s2
a4x= 11 cos 70°= 3. 76 m/s2
a4y= 11 sin 70° = -10.33m/s2
∑ax= 5 – 845 – 6..36 + 3.76
= - 6.05
∑ax= 8.66 + 3.07 – 6.36 – 10.33
= - 4.96

aR= ∑Fx2+∑Fy2=
aR= (-6.05)2+(-4.96)2 = 7.82
tgθ = ∑ay∑axθ=tg-1 ∑ay∑ax θ=-4.96-6.05 = 0.81983471
FR= 7.82 m/s2
<) 39°

d1x= 100 cos 0° = 100 km
d2x= 150 cos 50° =96.41 km
d2y= 150 sin 50° = 114.90km
d3y= 50 sin90° = 50 km
d4x= 180 cos 55°= 103.24km
d4y= 180 sin 55° = 147.44km
d5x=80 cos 180°= -80 km
d6x= 110 cos 30°= -95.26km
d6y= 110 sin 30° = - 55 km
d7y= 35 sin 270°= -35km
∑dx= 100 +...