siderurgia ejercicio

Realizar el Balance W = 9259 TM // I.B = 1.45
Pellets (P)
Fe2O3 = 50% =0.50P Gases
Fe3O2 = 15% =0.15PCO =?
FeO = 12% =0.12P CO2 =?
SiO2 = 20% =0.20P. N2 =?
Otros = 3% =0.03P

Nodulos (N)
MnO = 98% =0.98N . Polvos
Otros = 2% =0.02NFlux (F)
CaCO3 = 90% =0.90F
MgCO3 = 9% =0.09F
Otros =1% =0.01F

Coke
C = 98%
Volátiles = 1%
Cenizas = 1% .Arrabio
. Fe = 93% =0.93A
. C = 4% =0.04A
Viento Necesario. Si = 0.5% =0.05A
O2 = 23% =2018,89TM . Mn = 2% =0.02A
N2 = 77% =6758,89TM Otros = 0.5% =0.05A
Aire = 8777.78Escoria
SiO2 = 1793 TM
CaO = 0.043F =0.504(4753) = 2395.5TM
MgO = 0.043F = 0.043(4753) = 204.4TM
Reacciones de reducción del Si y el MN

SiO2(s) + C(s) Si(s) + 2CO(g)0.005A
MnO + C Mn(s) + CO(g)
0.02A

Cálculos de Wco en cada Rx

Wco(s) = x0.005A = 0.01A TM de CO

Wco (Mn) = x 0.02A = 0.0102A TM de CO

Por tanto:
0.01A + 0.0102A = 111
A= = 5495,05 TM de Arrabio

Calculo el peso...