Ingeniria

Cálculo de Fundación directa
Caso: Zapata Aislada

H | V |
1.5 | 1.5 |
1.5< | 1.7 |

DATOS |
σadm | 1 kg/cm2 |
B | 4 mts |
H | 2 mts |
V |1.5 |
Fc | 250 Kg/cm2 |
P | 125 t a kg 125000 kg |

Areq =V x PVadm =1.5 x 125000 kg1 kg/cm2 = 187500 cm2
B= A=Areq= 187500 cm2 = 4.33 cm~ 4.35
Paso 2σu= Parea = 125000187500 = 0.67 kg/cm2
σu
n=ß-b2=4.35-0.702=1.83
Mu= ßn22
Mu= 0.67 x 4.325 x 1.8322 = 48.80 t.md=Muμ*fx*ß=Mu48.88*1000*1000.1448*250*433=17.64cm≈20cm
μ | H= d + r |
d= h + r |
d= 20 cm |
r= 5 cm |
H= 15 cm |

0.1448 |
w | 0.18 |
Ju | 0.04 |
r | 5cm |
h | 15 |

C= n – d = 183 –20 = 163
Vu1 = σu * ß * c = 0.67 * 435 * 163 = 47506.35 Kg
Vu2= Vu1Ø*ß*d=147506.350.70*435*20= 7.80Kg
Vu2 ≤ 0.53 f'c
7.80 ≤ 0.53250
7.80 ≤ 8.38 CHEQUEAChequeo por punzonado:
Vu= Pu- σu ( b + d )2= 119573
bo=4(b + d )= 4(70+20)= 4(90)= 360
Vu=VuØ*ß*d= 119573d0.85*435*20=16.17Kg
Vu< 1.06f'c
16.17< 16.76 CHEQUEAChequeo por aplastamiento:
A1= 70 x 70 = 4900 cm2
A2= 400 x 400 = 160000 cm2
Pu max col= Ǿ (0.85 f’c A1)
Pu max col=0.70 (0.85 x 250x 4900)
Pu max base =535.5 x A1A2
Pu max base = 535.5 x 1600004900
Pu max base = 5.71
A1A2 ≤ 2 5.71 > 2
Pu max base = 2 x 535 kg = 1071 kg
Pu= 125000 Kg
Pu max col > P CHEQUEA
Pu max base > P CHEQUEA

Cálculo del Área del Acero
As= M∅ fy Ju d Ø fy=4200 kg/cm2
As= 48.80 x 1000 x 1000.90 x 4200 x 0.90 x 20
As= 71.72 cm2Distribución del Acero
As’= 71.724.00 = 17.9 cm2/m
As min = 2% x b x d=0.002 x 100 x 20 = 4cm
4,35
As min< As’ CHEQUEA

4,35
70
70

7 Ø 3/4" @ 14
20