Diseño de secciones de vigas

DISEÑO EN LAS SECCIONES DE LAS VIGAS
Nivel de diseño: 6, Pórtico: 2
Momentos de diseñoELEMENTO | Mui | MCL | Muj |
51 | -25.4 | 12.298 | -22.73 |
| 2.08 | | 3.2 |
52 | -26.8 | 14.09 | -26.83 |
53 | -22.63 | 10.354 | -22.56 |
|4.41 | | 4.46 |
54 | -25.31 | 14.217 | -27.5 |

F’c = 210 Kg/cm2 SECCION DE LA VIGA
Fy = 4200Kg/cm2
Pmax = 0.75pb

HALLANDO EL Mub: Mub = Rub x b x d^2
Rub = 48.948 según tabla
Mub = 48.948 x 30 x 51^2
Mub = 38.19 T-m
El Mub es mayor a todos los momentos de diseño entonces no existeacero en compresión
Procedo a diseñar por
Ku= | Mu/ (bxd2) |

TRAMO 51:
Mui= -25.4 T-m, b = 30, d = 54
| | | | |
Ku= | Mu/ (bxd2) | | | |
Ku= | 29.0352 | | | |
TABULANDO: || | | |
p | Ku | | | |
.0084 | 28.6 | | | |
p | 29.0352 | | p = | 0.0085 |
0.0086 | 29.21 | | | |
| | | | |
As=pxbxd | | | |
| | | | |
As= | 13.84 | cm2 | ||

Mui= 2.08 T-m, b = 30, d = 54
As^2 - 0.405f’c x b x d x As + 0.107 x Mu x f’c x b=0
A = 1
B = -0.405 x f’c x b
-0.405 x 0.21 x 30 x 54 = -137.781
C = 0.107 x Mu x f’c x b0.107 x 2.08 x 0.21 x 30 = 140.213
As = 1.03 cm2

Mucl = 12.298 T-m, b = 30, d = 54
| | | | |
Ku= | Mu/ (bxd2) | | | |
Ku= | 14.0581 | | | |
TABULANDO: | | | | |
p | Ku || | |
0.0038 | 13.72 | | | |
p | 14.0581 | | p = | 0.0039 |
0.004 | 14.41 | | | |
| | | | |
As=pxbxd | | | |
| | | | |
As= | 6.31 | cm2 | |

Muj = -22.73 T-m,b = 30, d = 54
| | | | |
Ku= | Mu/ (bxd2) | | | |
Ku= | 25.9831 | | | |
TABULANDO: | | | | |
p | Ku | | | |
0.0074 | 25.53 | | | |
p | 25.9831 | | p = |...