Ejercicio dfd

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  • Publicado : 17 de febrero de 2012
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Dfd (c)
1
1
1
0
0
5
1
1
N
7
0
1
12
N mod 10 = 4
4
1
4
'No'
13
4
1
4
'Si'
13
1
Dfd (c)
1
1
1
0
0
5
1
1
N
7
0
1
12
N mod 10 = 4
4
1
4
'No'
13
4
1
4'Si'
13
1
Dfd (c)
1
1
1
0
0
5
1
1
N
7
0
1
12
N mod 10 = 4
4
1
4
'No'
13
4
1
4
'Si'
13
1
Dfd (c)
1
1
1
0
0
5
1
1
N
7
0
1
12
N mod 10 = 4
4
1
4
'No'
13
41
4
'Si'
13
1
Dfd (c)
1
1
1
0
0
5
1
1
N
7
0
1
12
N mod 10 = 4
4
1
4
'No'
13
4
1
4
'Si'
13
1
Dfd (c)
1
1
1
0
0
5
1
1
N
7
0
1
12
N mod 10 = 4
4
1
4'No'
13
4
1
4
'Si'
13
1
Dfd (c)
1
1
1
0
0
5
1
1
N
7
0
1
12
N mod 10 = 4
4
1
4
'No'
13
4
1
4
'Si'
13
1
Dfd (c)
1
1
1
0
0
5
1
1
N
7
0
1
12
N mod 10 = 4
41
4
'No'
13
4
1
4
'Si'
13
1
Dfd (c)
1
1
1
0
0
5
1
1
N
7
0
1
12
N mod 10 = 4
4
1
4
'No'
13
4
1
4
'Si'
13
1
Dfd (c)
1
1
1
0
0
5
1
1
N
7
0
1
12
N mod10 = 4
4
1
4
'No'
13
4
1
4
'Si'
13
1
Dfd (c)
1
1
1
0
0
5
1
1
N
7
0
1
12
N mod 10 = 4
4
1
4
'No'
13
4
1
4
'Si'
13
1
Dfd (c)
1
1
1
0
0
5
1
1
N
7
0
112
N mod 10 = 4
4
1
4
'No'
13
4
1
4
'Si'
13
1
Dfd (c)
1
1
1
0
0
5
1
1
N
7
0
1
12
N mod 10 = 4
4
1
4
'No'
13
4
1
4
'Si'
13
1
Dfd (c)
1
1
1
0
0
5
1
1
N7
0
1
12
N mod 10 = 4
4
1
4
'No'
13
4
1
4
'Si'
13
1
Dfd (c)
1
1
1
0
0
5
1
1
N
7
0
1
12
N mod 10 = 4
4
1
4
'No'
13
4
1
4
'Si'
13
1
Dfd (c)
1
1
1
0
05
1
1
N
7
0
1
12
N mod 10 = 4
4
1
4
'No'
13
4
1
4
'Si'
13
1
Dfd (c)
1
1
1
0
0
5
1
1
N
7
0
1
12
N mod 10 = 4
4
1
4
'No'
13
4
1
4
'Si'
13
1
Dfd (c)
1
11
0
0
5
1
1
N
7
0
1
12
N mod 10 = 4
4
1
4
'No'
13
4
1
4
'Si'
13
1
Dfd (c)
1
1
1
0
0
5
1
1
N
7
0
1
12
N mod 10 = 4
4
1
4
'No'
13
4
1
4
'Si'
13
1...
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