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DEBER DE MATEMATICAS
NOMBRE: Jorge Chávez
CURSO: Aula 207
FECHA: 25/05/2011
Ejercicios para resolver
Simplificar las siguientes fracciones:

12 a3x4 +2 a2x518ab2x+3b2x2
=2a2x4(6a+x) 3 b2x(6a+x)
=2 a2x33 b2

3ax3+3a3x-6a2x2ax3-a3x
=3ax(x2-2ax+a2)ax(x2-a2)
=3axx-a2axx-ax+a
= 3(x-a)(x+a)

x2+y2+z2+2xy+2xz+2yzx2-y2-z2-2yz
=(x+y+z)2x+y+z(x-y-z)=(x+y+z)(x-y-z)
(x2-1)(1+ax)2-(x+a)2
= x+1(x-1)1+ax+x+a(1+ax-x-a)
= x+1(x-1)ax+1+x+1(ax-1-x+1)
=x+1(x-1)x+1a+1x-1(a-1)
= 1a2-1

a2x- xax+1
=a2-x2xa+xx
=a+xa-xxa+xx
=a-x

x-4x-32x-12x-x-3x-2
=2x2-x-4x+32x-12x2-4x-x+3x-2
= x-22x-1

x2-1x+1x2+2x+3x+1
=x2+x-22x+2x2+x+4x+62x+2
= x+2(x-1)x+2(x+3)
=(x-1)(x+3)

x+111+1+x1-x
= 1x+1x+1x = 11x+1
= 1(x+1)1

1+ 1a1+a+2a21-a
=1a1+a1+a(2a2)a
= a(2a+1)(a+1)a+1
=a2+1a+1

2xx2+y2 - 1x+y + yxy+x2
= xy2 - 1x+y + yxy+x2
=xy2 - xx+y + 1x+x2 = 1x

3aa2+ab-2b2+2ba2+3ab+2b2-2a+b
= 3a(a+b)(a.2a2) = 2b(a+3b)(a+2b2) = 2a+b=3a(a+b)(a+b) = 2b(a+b)(a-b2) = 2a+b
= 3aba-b

x+12x+2 - x-12x+2 + 4x1+x2 + x2+1x2-1
=4x1-x2+ x2+1x2-1
= 4(x)1-x2+ (x2+1)x2-1
= x1 + x-1x+1
=x(x-1)x(x+1
=x+1x+1

2-12-22+1X
2-12-22X+1X2-12-2X2X+1
2-14X+2-2X2X+1
2-2X+14X+2-2X

4X+2X+14X+2-2X
6X+12X+2

x-11-x1-1x2-x
x-x2-11-xx2-x-1x2-x

x-x2-1(x2-x-1)1-x(x2-x)
-x4-2x3+x2+1-x3+2x2-x
1a+b+ba2-b2-aa2+b2+2a3a4-b4a4-b4×a2+b2×a2-b2a+b+b(a4-b4×a2+b2×a+b)a2-b2-a(a4-b4×a2±×a+b)a2+b2+2a3(a2-b2×a2+b2×a+b)a4-b4
ax+ay-bx-byam-bm-an+bn
ax+y-b(x-y)am-an-bm+bn=a-b(x2-y2)am-n-b(m+n)=a-b(x2-y2)a-b(m2-n2)=(x2-y2)(m2-n2)x+5x2+7x+10-x-1x2+x-2
x+5x+5x+2+x-1x+2x-1
x+5x-1-[x-1x+5]x+5x+2(x-1)=x2-x+5x-5-[x2+5x-x-5]x+5x+2(x-1)
x2-4x-5-x2-4x+5x+5x+2(x-1)
0
2522-95212510
252052-952051520
520[252-95]520
50-45
5mn+n2m2nm2-1m+1n
m3+n3m2nn2-mn-m2m2n
m+n(m2-mn+n2)(m2-mn+n2)
m+n
Si A=1x-yx+y2x3;B=1+yx3 ;Determinar BA
1+y3x3x2-xy+y2y3
x3+y3x3x2-xy+y2y3
x+yx2-xy+y2x3x2-xy+y2y3
(x+y)x31y3
y3(x+y)x3
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