Estadistica

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HISTOGRAMA DE FRECUENCIAS |
CLASE | F. | Xi | FRONTERAS DE CLASE | Fr. |
1.60-1.62 | 5 | 1.61 | 1.55-1.67 | 0.05 |
1.63-1.65 | 18 | 1.64 | 1.67-1.70 | 0.18 |1.66-1.68 | 42 | 1.67 | 1.70-1.73 | 0.42 |
1.69-1.71 | 27 | 1.70 | 1.73-1.76 | 0.27 |
1.72-1.74 | 8 | 1.73 | 1.76-1.79 | 0.08 |

GRAFICA DE PASTEL |
CLASE | F |(Fr)X(360)=(Fr)(360) |
1.60 – 1.62 | 5 | 0.05 x 360 = 18 |
1.63 – 1.65 | 18 | 0.18 x 360 = 64.8 |
1.66 – 1.68 | 42 | 0.42 x 360 = 151.2 |
1.69 – 1.71 | 27 | 0.27 x360 = 97.2 |
1.72 – 1.74 | 8 | 0.08 x 360 = 28.8 |

MEDIA
∑FXi /n =x =167.45/100 = x =1.6745
X = 1.6745

MEDIANA
Li= 1.68 + 1.69/2 = 1.685
nº de datos = 100f.a= 65
f.m= 42
w= -0.03
FORMULA: Me= Li + (n/2 - fa)w
f.m

Me= 1.685 + (100/2-65) – 0.3f.m
Me= 1.327

MODA
Li = 1.62 + 1.63 = 1.625
2

Δ1= 5-18 = 13 Δ2= 42-18= 24

FORMULA
Mo = Li + Δ1
Δ1 + Δ2 w

Mo = 1.625 + (13/ 13+24) – 0.3

Mo = 1.946

VARIANZAFORMULA DE VARIANZA :

Xi – X | (Xi - X) | F(Xi - X) |
0.1355 | 0.01836025 | 0.09180125 |
-0.0345 | 0.00119025 | 0.0214245 |
-0.0045 | 0.00002025 |0.0008505 |
0.0255 | 0.00065025 | 0.01755675 |
0.555 | 0.00308025 | 0.024642 |
0.156275=∑f (xi –x) |

VARIANZA

∑f (xi –x) = 0.156275 = 0.156275 = 0.0157853
n-1100-1 99

DESVIACION ESTANDAR

FORMULA ∑f (xi –x) = 0.00157853 = 0.39730785
n-1
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