Explotac de equipos

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• Publicado : 20 de noviembre de 2011

Vista previa del texto
Volumen total que le corresponde a la base.
Vc base = (0.2m)(7.5m)(6150m) = 9225m3c
Volumen total que le corresponde a la sub-base.
Vcsub-base = (0.25m)(7.5m)(6150m) : 11531m3cAbundamiento.
Ab = γbγs = 19561720 =1.14
Enjuta miento.
Enj = γbγc = 19562082= 0.94
Volumen suelto del banco de material de la base.
Vs base = 9225(1.14)0.94= 11187.77 m3s
Volumen suelto del banco dematerial de la base.
VS sub base = 11531.25(1.14)0.94 = 13984.71m3s
Volumen en banco de material de la base.
Vb = VsAb= 11187.771.14= 9813.83 m3b
Volumen en banco de material de la sub base.
Vb =13984.71 1.14= 12267.29 m3b
γb = 1956
γs= 1720
γc = 2082
A-Subbase
Tm=30seg E=0.8
Vs: 5002.66m3
N0 ciclos : 5002.66/11.7=428
Va 1era = 3.4km/hr
VR 3era = 13.8km/hr
ta=(90)(3600)/(3.4)(1000) =95.29seg
tR=(90)(3600)/(13.8)(1000) =23.48seg
Tt=( tm+ta+tR)(N0C)/(3600xE)
Tt=( 30+95.29+23.48)(428)/(3600x0.8)=22.12hrB-base
Vs: 4638.83m3
N0 ciclos :4638.83 /11.7=397
Tt=( tm+ta+tR)(N0C)/(3600xE)
Tt=( 30+95.29+23.48)(397)/(3600x0.8)=20.51hr
Rendimiento
R = 11187.77 49.43=226.33m3/hr
A-Subbase
5002.66/226.33= 22.103hrs
B-base
4638.83/226.33= 20.496hrs
C-base
6548.94/226.33= 28.935hrs
D-Subbase
8982.05/226.33= 39.686hrs
Tt del tractor=(39.686+28.935+20.496+22.103)=111.22hrs
Volumen a excavar por banco
Banco A (subbase):
Vc=1.2+0.4+0.610007.50.25=4125 m3
Vs=(4125)(13984.71)11531.25=5002.66m3
Vb=(4125)(12267.29)11531.25=4388.3 m3
Banco D (subbase):Vc=11531.25-4125=7406.25m3
Vs=13984.71-5002.66=8982.05m3
Vb=12267.29-4388.3=7878.99m3

Banco B (base):
Vc=1.2+0.4+0.9510007.50.20=3825m3
Vs=(3825)(11187.77)9225=4638.83m3Vb=(3825)(9813.83)9225=4069.15m3

Banco C (base):
Vc=9225-3825=5400m3
Vs=1187.77-4638.83=6548.94m3
Vb=9813.83-4069.15=5744.68m3

Volumen a ocupar en los puntos establecidos

Punto 1 (subbase):
Vc=1.2510000.257.5=3000m3...