Normalidad

Páginas: 2 (380 palabras) Publicado: 3 de marzo de 2012
PARTE A
gestandar=gmuestra/mlmuestra=1.376/25=0.05504
Peq estándar=PM/∆ 294/6=49

K2Cr2O7 | | Tiosulfato de sodio | | |
1.376 g | KI g | 6M | | | |
K2Cr2O7 ml | | HCl ml| mL | Nt= g estandar/peq estandar*L titulante | Nt Normalidad titulante |
10 | 1 | 5 | 11.65 | (0.05504/(49*0.01165)) | 0.09641762 |
10 | 1 | 5 | 11.7 | (0.05504/(49*0.0117)) | 0.09600558 |10 | 1 | 5 | 11.9 | (0.05504/(49*0.0119)) | 0.09439204 |
10 | 1 | 5 | 11.5 | (0.05504/(49*0.0115)) | 0.09767524 |Npromedio=0.09654004eq/l
Nestandar=gestandar/Pe*Le=1.376/49*0.25=0.1123
Nt=Ne*Le/Lt | Normalidad del titulante |
0.1123*0.01/0.01165 | 0.09639485 |
0.1123*0.01/0.0117 | 0.09598291 |0.1123*0.01/0.0119 | 0.09436975 |
0.1123*0.01/0.0115 | 0.09765217 |
Npromedio= 0.096099919

PARTE B
Inicial
Cl | KI g | 6M | 2 gotas almidón |
mL | | HClml | Tiosulfato de sodio ml |
10 | 0.5 | 5 | 0.1 |
10 | 0.5 | 5 | 0.1 |

PeCl=35.453/2=17.7265=18 | Nt=0.0965 | | | |
ga=Nt*Lt*Peq Cl | gCl | % P/v= (ga/ mLm )*100 | %p/v | ppm |0.0965*0.0001*18 | 0.0001737 | 0.0001737/0.0001*100 | 173.7 | 173700000 |
0.0965*0.0001*18 | 0.0001737 | 0.0001737/0.0001*100 | 173.7 | 173700000 |

Final
CL | KI g | 6M | 2 gotas almidon |
mL| | HCl ml | Tiosulfato de sodio ml |
10 | 0.5 | 5 | 0.15 |
10 | 0.5 | 5 | 0.1 |

PeCl=35.453/2=17.7265=18 | Nt=0.0965 | | | |
ga=Nt*Lt*Peq Cl | gCl | % P/v= (ga/ mLm )*100 | %p/v| ppm |
0.0965*0.00015*18 | 0.00026055 | 0.00026055/0.00015*100 | 173.7 | 1737000 |
0.0965*0.0001*18 | 0.0001737 | 0.0001737/0.0001*100 | 173.7 | 1737000 |

Parte C
PeCl=35.453/2=17.7265=18 |Nt=0.0965 |

KI g | Agua destilada mL | H2SO4 mL | Na2S2O3 (2gotas almidon) |
1 | 100 | 5 | 0.05 |
0.5 | 100 | 5 | 0.05 |

gCl= N*Lt*Peq a | g Cl | % P/v= (ga/ mLm )*100 | ppm Cl |...
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