# Practica 3 de termodinamica

Solo disponible en BuenasTareas
• Páginas : 3 (544 palabras )
• Descarga(s) : 0
• Publicado : 11 de marzo de 2012

Vista previa del texto
Tabla de Datos
Experimentales:

Altura Total (hT)(cm) | Altura (hc)(cm) | Altura (ha)(cm) |
42.5 | 26 | 26 |
40.5 | 25 | 30.5 |
37.5 | 23.5 | 36.5 |
34.5 | 22 | 43.5 |
31.5 | 20.4 |51.6 |
22.8 | 14.6 | 78.1 |
Di= 0.415 | hbarom = 0.585 | tamb = 27.5° C |

Cálculos:

ρHg = 13595.08 – 2.466(tamb) + 3*10-4 (tamb)
=13595.08 –2.466(27.5° C) + 3*10-4 (27.5° C)
= 13,525.27325 Kg/m3

2. Valores de ha y hc en metros

Factor de conversión
1 cm1m100cm

conversión | hc (m) | | conversión | ha (m) |26/100 | 0.26 | | 26/100 | 0.26 |
25/100 | 0.25 | | 30.5/100 | 0.305 |
23.5/100 | 0.235 | | 36.5/100 | 0.365 |
22/100 | 0.22 | | 43.5/100 | 0.435 |
20.4/100 | 0.204 | | 51.6/100 | 0.516 |14.6/100 | 0.146 | | 78.1/100 | 0.781 |

3. Altura Neta de Mercurio en Metros

hHg= ha - hc

hHg1 = ha1 - hc1
= (0.26m – 0.26m)
= 0m

hHg2 = ha2 - hc 2
= (0.305 m– 0.25m)
= 0.055m

hHg3= ha3 - hc3
= (0.365m – 0.235m)
= 0.13m

hHg4 = ha4 – hc4
= (0.435m – 0.22m)
= 0.215m

hHg5 = ha5 - hc5
= (0.516m –0.204m)
= 0.312m

hHg6 = ha6 - hc6
= (0.781m – 0.146m)
= 0.635m

4. Presion Hidrostática (Ph) del mercurio en pascales (Pa)

Ph = ρHg (g) (hhg)

Ph1 = ρHg (g) (hhg1)= (13,525.27325 Kg/m3) (9.78m/s2) (0.000m)1N1Kg*m/s21 Pa1 N/m2
= 0 Pa

Ph2 = ρHg (g) (hhg2)
= (13,525.27325 Kg/m3) (9.78m/s2) (0.055m) 1N1Kg*m/s21 Pa1 N/m2
= 7,275.244481Pa

Ph3 = ρHg (g) (hhg3)
= (13,525.27325 Kg/m3) (9.78m/s2) (0.130m) 1N1Kg*m/s21 Pa1 N/m2
= 17,196.03241 Pa

Ph4 = ρHg (g) (hhg4)
= (13,525.27325 Kg/m3) (9.78m/s2) (0.215m)1N1Kg*m/s21 Pa1 N/m2
= 28,439.59206 Pa

Ph5 = ρHg (g) (hhg5)
= (13,525.27325 Kg/m3) (9.78m/s2) (0.312m) 1N1Kg*m/s21 Pa1 N/m2
= 41,270.47778 Pa
Ph6 = ρHg (g) (hhg6)
=...