Students Subnetwork Book

11111110
1010100
10001111100
1011100101011100
101100011101001
1011110100011010
00001010010110010
1001010101100111
1111010101000101
1101001101010011
001010010101010
1010101000110010
010101001011000
110101100011010
11010100001011
001010100110
1001010010
10011000
0101
11010011
10000110
10010101
00011011
001 IP Addressing
and
Subnetting
Workbook
Version 1.2
IP AddressClasses
Class A 1 – 127 (Network 127 is reserved for loopback and internal testing)
Leading bit pattern 0 00000000.00000000.00000000.00000000
Class B 128 – 191 Leading bit pattern 10 10000000.00000000.00000000.00000000
Class C 192 – 223 Leading bit pattern 110 11000000.00000000.00000000.00000000
Class D 224 – 239 (Reserved for multicast)
Class E 240 – 255 (Reserved for experimental, used forresearch)
Private Address Space
Class A 10.0.0.0 to 10.255.255.255
Class B 172.16.0.0 to 172.31.255.255
Class C 192.168.0.0 to 192.168.255.255
Default Subnet Masks
Class A 255.0.0.0
Class B 255.255.0.0
Class C 255.255.255.0
Network . Host . Host . Host
Network . Network . Host . Host
Network . Network . Network . Host
Inside Cover
Produced by: Robb Jones
jonesr@careertech.netFrederick County Career & Technology Center
Cisco Networking Academy
Frederick County Public Schools
Frederick, Maryland, USA
Special Thanks to Melvin Baker and Jim Dorsch
for taking the time to check this workbook for errors.
Binary To Decimal Conversion
128 64 32 16 8 4 2 1 Answers Scratch Area
1 0 0 1 0 0 1 0 146
0 1 1 1 0 1 1 1 119
1 1 1 1 1 1 1 1
1 1 0 0 0 1 0 1
1 1 1 1 0 1 1 0
0 0 01 0 0 1 1
1 0 0 0 0 0 0 1
0 0 1 1 0 0 0 1
0 1 1 1 1 0 0 0
1 1 1 1 0 0 0 0
0 0 1 1 1 0 1 1
0 0 0 0 0 1 1 1
00011011
10101010
01101111
11111000
00100000
01010101
00111110
00000011
11101101
11000000
128
16
2
146
64
32
16
4
21
119
1
Decimal To Binary Conversion
128 64 32 16 8 4 2 1 = 255 Scratch Area
_________________________________________ 238_________________________________________ 34
_________________________________________ 123
_________________________________________ 50
_________________________________________ 255
_________________________________________ 200
_________________________________________ 10
_________________________________________ 138
_________________________________________ 1
_________________________________________ 13_________________________________________ 250
_________________________________________ 107
_________________________________________ 224
_________________________________________ 114
_________________________________________ 192
_________________________________________ 172
_________________________________________ 100
_________________________________________ 119_________________________________________ 57
_________________________________________ 98
_________________________________________ 179
_________________________________________ 2
238
-128
110
-64
46
-32
14
-8
6
-4
2
-2
0
1 1 1 0 1 1 1 0 34
-32
2
-2
0
0 0 1 0 0 0 1 0
Use all 8 bits for each problem
2
Address Class Identification
Address Class
10.250.1.1 _____
150.10.15.0 _____
192.14.2.0 _____148.17.9.1 _____
193.42.1.1 _____
126.8.156.0 _____
220.200.23.1 _____
230.230.45.58 _____
177.100.18.4 _____
119.18.45.0 _____
249.240.80.78 _____
199.155.77.56 _____
117.89.56.45 _____
215.45.45.0 _____
199.200.15.0 _____
95.0.21.90 _____
33.0.0.0 _____
158.98.80.0 _____
219.21.56.0 _____
A
B
3
Network & Host Identification
Circle the network portion
of these addresses:177.100.18.4
119.18.45.0
209.240.80.78
199.155.77.56
117.89.56.45
215.45.45.0
192.200.15.0
95.0.21.90
33.0.0.0
158.98.80.0
217.21.56.0
10.250.1.1
150.10.15.0
192.14.2.0
148.17.9.1
193.42.1.1
126.8.156.0
220.200.23.1
Circle the host portion of
these addresses:
10.15.123.50
171.2.199.31
198.125.87.177
223.250.200.222
17.45.222.45
126.201.54.231
191.41.35.112
155.25.169.227...