Termodinamica

1.- Calcular la densidad del mercurio (ρHg) a temperatura ambiente
ρHg=13595.08-2.46625℃+0.000325℃2
ρHg=13533.6175 Kg/m3
2.- alcula la presión barmetrica ( Pbarometrica )
Pbaro = (ρHg)glocal(hbarometrica)
Pbaro = (13533.6175 Kg/m3) (9.78 m/s2)(.585 mHg)
Pbaro =77429.8858 Pa
3.- Calcular los valores de la presión hidrostática del mercurio PHg en Pascales
PHg= 13533.6175Kgm3)9.78ms2 0.388m-0.305m=10588.70233Pa
PHg= 13533.6175Kgm3) 9.78ms2 0.42m-0.265m=20515.61077Pa
PHg= 13533.6175Kgm3) 9.78ms2 0.46m-0.226m =30971.95432Pa
PHg= 13533.6175Kgm3) 9.78ms2 0.487m-0.195m=38648.46351Pa
PHg= 13533.6175Kgm3) 9.78ms2 0.513m-0.174m =44869.62613Pa
PHg= 13533.6175Kgm3) 9.78ms2 0.529m-0.154m =49634.54218Pa
PHg= 13533.6175Kgm3) 9.78ms2 0.545m-0.14m =53605.30556Pa
PHg=13533.6175Kgm3) 9.78ms2 0.559m-0.127m =57178.99259Pa
4.-Calcula la densidad del agua (ρH2O) a temperatura ambiente
ρH2O=0.99998+3.5x10-5(Tambiente)-6.0x10-6(Tambiente)2ρH2O=0.99998+3.5x10-525℃-6.0x10-6(25℃)2
ρH2O=0.997105g/mL

5.- Transformar la densidad del agua a Kg/m3
ρH2O=0.997105gmL 1Kg1000g1x106mL1m3=997.105 Kg/m3
6.- Calcula los valores de la presión hidrostática del agua (PH2O) enPascales
PH2O=ρH2Oglocal ( hT- hs )
PH2O=ρH2997.105Kgm39.78ms2 1.03m-0.385m=6289.838051 Pa
PH2O=ρH2997.105Kgm39.78ms2 1.03m-0.42m=5948.529009 Pa
PH2O=ρH2997.105Kgm39.78ms2 1.03m-0.46m=5558.461533 PaPH2O=ρH2997.105Kgm39.78ms2 1.03m-0.487m=5295.165987 Pa
PH2O=ρH2997.105Kgm39.78ms2 1.03m-0.513m=5041.622127Pa
PH2O=ρH2997.105Kgm39.78ms2 1.03m-0.529m=4885.595137 Pa
PH2O=ρH2997.105Kgm39.78ms21.03m-0.545m=4729.568147 Pa
PH2O=ρH2997.105Kgm39.78ms2 1.03m-0.559m=4593.04453Pa
7.- Calcular los valores de la presión de vacio dentro del matraz
pvacio= PH2O+PHg

pvacio= 6289.838051 Pa+10588.70233Pa=16878.5403 Pa
pvacio= 5948.529009 Pa+ 20515.61077Pa= 26464.13978 Pa
pvacio=5558.461533 Pa+ 30971.95432Pa=36530.41585 Pa
pvacio= 5295.165987 Pa+38648.46351Pa=43943.9295 Pa
pvacio=...